python print escape backslash

Question

I need python to generate exactly such string literal:

e.b=\"e\"

But I can't come up with idea how to do so. I was trying:

r'e.b=\"e\"'      =>     e.b=\\"e\\"
"""e.b=\"e\""""   =>     e.b="e"

And many other possibilities but any ends up with exactly e.b=\"e\"

Any ideas?

the first one (r'e.b=\"e\"') should be right. When the python interpreter prints, it will show single ` characters as \`, but if you output it to a file, it should really be just a single ``. — R Nar
– R Nar, Commented May 25, 2016 at 19:04
Your raw string does what you want. Try printing it with print, or writing it to a file. And print its length, which should be 9. — PM 2Ring
– PM 2Ring, Commented May 25, 2016 at 19:07

Community · Accepted Answer · 2017-05-23 11:58:39Z

6

Well, you had it right the first time, except that you examined the repr of the string you created, instead of the string itself:

s = r'e.b=\"e\"'
s  # this is the repr() of the string
=> 'e.b=\\"e\\"'
print(repr(s))
=> 'e.b=\\"e\\"'
print(s)  # this is what you want
=> e.b=\"e\"

Bottom line, s=r'e.b=\"e\"' is what you want.

edited May 23, 2017 at 11:58

CommunityBot

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answered May 25, 2016 at 19:04

shx2

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Comments

Rasmi Ranjan Nayak · Accepted Answer · 2016-05-25 19:04:36Z

0

Are you thinking of printing like this?

import re
d = re.escape(r'e.b=\"e\"')
print d

answered May 25, 2016 at 19:04

Rasmi Ranjan Nayak

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