How to remove a string from left side of a bigger string in PHP?

Question

I have a variable which can send me data like:-

thumb_8_2393_Shades 1.jpg, hanger-cloth.jpg & Red-Lehenga-1.jpg;

Now, when the value will have 'thumb_' at the left side, I want to discard the 'thumb_' string from the full value.

So I wrote this code:-

$pImgBig = trim($pI['image'],'thumb');

What the issue I am facing is, it is also removing the 'h' from the 'hanger-cloth.jpg'.

How can I overcome this issue?

@RamRaider and what if the string contains 'thumb_' in the middle, but not on the left? — Saswat
– Saswat, Commented Jul 18, 2016 at 7:01
@Anant Precisely, no. It doesn't contain comma separated values. — Saswat
– Saswat, Commented Jul 18, 2016 at 7:02

Death-is-the-real-truth · Accepted Answer · 2016-07-18 07:25:56Z

1

You can use preg_replace() like below:-

$pImgBig = preg_replace('/^thumb_/','',$pI['image']);

<?php
$data = 'hanger-cloth.jpg';

$data = preg_replace('/^thumb_/','',$data);
echo $data;

$data1 = 'thumb_8_2393_Shades 1.jpg';

$data1 = preg_replace('/^thumb_/','',$data1);
echo $data1;

Output:-https://eval.in/606785

@RaimRaider give a very nice sugestion of using str_replace() in correct way like below:-

<?php
$data = 'hanger-cloth.jpg';

$data =  substr($data,0,6)==='thumb_' ? str_replace( 'thumb_', '', $data ) : $data;
echo $data;

$data1 = 'thumb_8_2393_Shades 1.jpg';

$data1 =  substr($data1,0,6)==='thumb_' ? str_replace( 'thumb_', '', $data1 ) : $data1;
echo $data1;

$filename=substr($filename,0,6)==='thumb_' ? str_replace( 'thumb_', '', $filename ) : $filename;

Output:-https://eval.in/606800

edited Jul 18, 2016 at 7:25

answered Jul 18, 2016 at 7:07

Death-is-the-real-truth

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3 Comments

AD7six Over a year ago

You have to use not true, and using a regex for something like this often leads to problems, as regexes are so often misunderstood.

Nijesh Hirpara Over a year ago

In this case we have to use regex, as we only require to remove sub-string at the beginning of the string. preg_replace('/^thumb_/','',$data)

Nijesh Hirpara Over a year ago

@anant, you can't use str_replace. Run your code for the value 8_2393_thumb_Shades 1.jpg

RomanPerekhrest · Accepted Answer · 2016-07-18 07:16:08Z

1

The solution using strpos and substr functions:

$images = ['thumb_8_2393_Shades 1.jpg','hanger-cloth.jpg', 'Red-Lehenga-1.jpg'];
foreach ($images as &$img) {
    if (strpos($img, 'thumb_') === 0) {  // if file name starts with 'thumb_'
        $img = substr($img, 6);
    }
}

print_r($images);

The output:

Array
(
    [0] => 8_2393_Shades 1.jpg
    [1] => hanger-cloth.jpg
    [2] => Red-Lehenga-1.jpg
)

answered Jul 18, 2016 at 7:16

RomanPerekhrest

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