PHP Find any array value in a string and show the found value

Question

I hope you can help me, I have an array with some filter words:

$dang=array('foo','bar','baz','qux');

User can write a text, I am getting it in a variable:

$answ=$_GET[answ];

If user write a text like: "I like this cabaret, it's so foo.", I want to print this:

Found: bar

"bar" is found in "cabaret", (First ocurrence only).

I found this function here Find first occurance of array value in a string

$firstMatch = array_shift(array_intersect(str_word_count(strtolower($answ), 1), $dang));

it's works, sadly it finds words only (text separated by spaces).

Any way to do it for full text?

I tried iterating the array and search using stripos(), it's a good way to do it, do you know something 'shorter'? maybe a regular exp? — stramin
– stramin, Commented Jul 27, 2016 at 14:55

Brett Gregson · Accepted Answer · 2016-07-27 14:56:51Z

2

You can loop the array using foreach() and use strpos() to check if the value exists in the string:

$string = "Hello world";

foreach ( $dang as $dong ) {
    if ( strpos($string, $dong) !== false ) {
        echo "Found: ".$dong; 
    }
}

strpos() returns false if the needle was not found, otherwise the position of the start of the needle in the haystack (0 being the first character)

edited Jul 27, 2016 at 14:56

answered Jul 27, 2016 at 14:53

Brett Gregson

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1 Comment

Martin Over a year ago

This answer is right. You should add a foreach to iterate your array with your filters and it'll do what you need.

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