Usage of String.range in Swift 3.0

Question

let us = "http://example.com"
let range = us.rangeOfString("(?<=://)[^.]+(?=.com)", options:.RegularExpressionSearch)
if range != nil {
    let found = us.substringWithRange(range!)
    print("found: \(found)") // found: example
}

This code extracts substring between backslashes and dot com in Swift 2. I searched Internet and I found that rangeOfString changed to range().

But still I could not make the code work in Swift 3.0. Could you help me ?

edit : I'm using swift 3 07-25 build.

Nirav D · Accepted Answer · 2016-08-24 14:35:19Z

34

In swift 3.0 rangeOfString syntax changed like this.

let us = "http://example.com"
let range = us.range(of:"(?<=://)[^.]+(?=.com)", options:.regularExpression)
if range != nil {
     let found = us.substring(with: range!)
     print("found: \(found)") // found: example
}

edited Aug 24, 2016 at 14:35

answered Aug 24, 2016 at 14:29

Nirav D

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4 Comments

Fuzuli Over a year ago

it gives following errors: 1- Type 'CompareOptions' (aka 'NSString.CompareOptions') has no member 'RegularExpressionSearch' 2- Value of type 'String' has no member 'substringWithRange'

pedrouan Over a year ago

@H.Cliff check an answer below for latest SDK

Nirav D Over a year ago

@LeoDabus editted for that. Sorry forgot to set that also for swift 3.

Nirav D Over a year ago

Welcome mate, Happy Coding :) but i'm NDoc

pkamb · Accepted Answer · 2017-11-14 00:30:39Z

7

In latest swift 3.0 using Xcode 8 Beta 6 (latest updates to SDK):

let us = "http://example.com"
let range = us.range(of: "(?<=://)[^.]+(?=.com)", options: .regularExpression)
if range != nil {
    let found = us.substring(with: range!)
    print("found: \(found)") // found: example
}

edited Nov 14, 2017 at 0:30

pkamb

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answered Aug 24, 2016 at 14:33

pedrouan

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