How to dynamically change variable in php

Question

I have a token for a specific ID number which is 494

$url = api.pipedrive.com/v1/deals/494/products?start=0&api_token=7ecb71622dadd2faae2732bfe73b09381150c967;

I want to change the number 494 to any number.

I've made an illogical code to begin with.

Any guide on how to do this?

$url = "https://api.pipedrive.com/v1/deals/";
$id = 494;
$api = "/products?start=0&api_token=7ecb71622dadd2faae2732bfe73b09381150c967";

$response = file_get_contents($url+$id+$api);
echo $response;

$object = json_decode($response, true);

I got the errorL

Warning: file_get_contents(494): failed to open stream: No such file or directory

Could you clarify what problem you want to solve? Because it just sounds like you want to redeclare variables: $id = 123; — Thomas
– Thomas, Commented Oct 2, 2016 at 15:10
@Thomas yeah, I wanted to be able to change the $id dynamically and call the complete token the same as the first $url above — blakcat7
– blakcat7, Commented Oct 2, 2016 at 15:14
@Devon yeah I figured too. Do you know anyway to call the $url, $id, and $api in file_get_contents? — blakcat7
– blakcat7, Commented Oct 2, 2016 at 15:16
@AntheaMarie the PHP manual is useful: php.net/manual/en/language.operators.string.php — Devon Bessemer
– Devon Bessemer, Commented Oct 2, 2016 at 15:17

Risul Islam · Accepted Answer · 2016-10-02 15:16:51Z

2

You are using '+' operator to concatenate. Which sums two variable. You need to use concatenation operator ('.') not '+'

$url = $url.$id.$api;

edited Oct 2, 2016 at 15:16

answered Oct 2, 2016 at 15:11

Risul Islam

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Rax Weber · Accepted Answer · 2016-10-02 15:22:16Z

0

In PHP, . is used for string concatenation. Also you can use the .= to append a string to a string variable. Example:

$str = "Hello";
$str2 = $str . "Anthea"; // $str2 = "Hello Anthea"

Or

$str = "Hello";
$str .= "Anthea"; // $str = "Hello Anthea"

answered Oct 2, 2016 at 15:22

Rax Weber

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