Remove all repeated values in array and leave the ones that don't repeat in Javascript [closed]

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Example: I have an array with repeated values 1 and 2

[1,1,2,2,3,4,5]

I want the result of that array to be an array of the values that dont repeat.

[3,4,5]

Make an object whose properties are the values from the array, and values are the count of repetitions. After you're done, find all the keys with value = 1. — Barmar
– Barmar, Commented Oct 13, 2016 at 19:22
@Barmar has the method I prefer to use-- quick and dirty, but it gets the job done efficiently. — Alexander Nied
– Alexander Nied, Commented Oct 13, 2016 at 19:24
@Bergi it's not a duplicate of that question. That will keep one copy of every value, he wants only the values that started with 1 copy. — Barmar
– Barmar, Commented Oct 13, 2016 at 19:29
i'm trying to use filter function. [1,1,2,2,3,4,5].filter(function(c,i,a){ return (a.indexOf(c) < i); but Im not getting anywhere. — avatarZuko
– avatarZuko, Commented Oct 13, 2016 at 19:36
@Barmar Ah, you're right. How about stackoverflow.com/questions/34498659/… then? — Bergi
– Bergi, Commented Oct 13, 2016 at 19:39

Thalaivar · Accepted Answer · 2016-10-13 19:39:21Z

1

var arr = [1,1,2,2,3,4,5]

arr = arr.filter (function (value, index, array) {
    return array.indexOf (value) == array.lastIndexOf(value);
});

console.log(arr);

https://jsfiddle.net/qducmzqk/

answered Oct 13, 2016 at 19:39

Thalaivar

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Christian Vincenzo Traina · Accepted Answer · 2016-10-13 19:42:04Z

0

Without JQuery, you can use the filter method:

var nums = [1,1,2,2,3,4,5]
nums = nums.filter(function(val){
  return nums.indexOf(val)===nums.lastIndexOf(val);
});
// [3,4,5]

Otherwise, if in future you want to preserve repeated numbers, you can use:

for(var i=0; i<nums.length; i++) if(i!==nums.lastIndexOf(nums[i])) nums.splice(i, 1);
// [1,2,3,4,5]

edited Oct 13, 2016 at 19:42

answered Oct 13, 2016 at 19:38

Christian Vincenzo Traina

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1 Comment

avatarZuko Over a year ago

thanks criz it worked!

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