Random word generator python

Question

So this is the code I have. The outcome is something along "['jjjjjjj', 'tt', 'dddd', 'eeeeeeeee']". How can I change the list comprehension to allow for the function random.choice to repeat for each letter of each 'word'?

lista=[random.randint(1,10)*random.choice(string.ascii_letters) for i in range(random.randint(1,10))]

Sorry I didn't get what you want.

Pan Long
– Pan Long

2016-10-16 15:49:10 +00:00
Commented Oct 16, 2016 at 15:49 — Pan Long
– Pan Long, Commented Oct 16, 2016 at 15:49

AncientOwl · Accepted Answer · 2016-10-16 15:56:41Z

2

I suppose you mean you want "abcd" and "jdhn" instead of "aaaa" and "jjjj" for the purpose of testing a sorting algorithm or some such.

If so, try this

lista=["".join(random.choice(string.ascii_letters) for j in range(random.randint(1,10)) ) for i in range(random.randint(1,10)) ]

answered Oct 16, 2016 at 15:56

AncientOwl

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Comments

Mohammad Athar · Accepted Answer · 2016-10-16 15:57:32Z

0

You'll need a nested list comorehension. You need to rerun random.choice for every letter. Something along the lines of

[ [Random.choice(string.asciiletters) for x in range(y)]  for you in range(5)]

Will give you 5 'words' each of length y.

answered Oct 16, 2016 at 15:57

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