Matlab determine index position in matrix

Question

Hin everyone..I have matrix

col = [1 2 3 9 10 15 16 17]

I need to divide A into 3 with length B = [3 2 3], result required :

col1 = [1 2 3] -> from col(1:3)
col2 = [9 10] -> from col(4:5)
col3 = [15 16 17] -> from col(6:8)

Thank you so much...

rahnema1 · Accepted Answer · 2016-11-02 05:33:46Z

2

mat2cell can be use:

A = [1 2 3 9 10 15 16 17];
B = [3 2 3];
mat2cell(A,1, B)

Result:

{
  [1,1] =

     1   2   3

  [1,2] =

      9   10

  [1,3] =

     15   16   17

}

answered Nov 2, 2016 at 5:33

rahnema1

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2 Comments

Thank you @rahnema1

@rahnema1 nice. +1

Marcin · Accepted Answer · 2016-11-02 05:11:34Z

1

I assume that lenghts in B match col length, so every element is accounted for. If so, you can do it using simple for loop as follows:

col = [1 2 3 9 10 15 16 17];

B = [3 2 3];

start_idx = 1;
for b = B
    col_part = col(start_idx : start_idx+b-1)
    start_idx = start_idx+b;
end

Results in:

col_part =

     1     2     3


col_part =

     9    10


col_part =

    15    16    17

answered Nov 2, 2016 at 5:11

Marcin

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