C - Arrays. Change only specific values

Question

I am trying to search through an array, and only check specific values (the 4th,5th and so on)- ((0+n*4) and (3+n*4). The first one found will be checked and if it has a value of 0 will it be changed to 1 and then the program should stop. If not it will try the next value and so on.. I have the following code, but it doesn't stop ..it makes all the values 1 at once.. Any suggestions?

        {
        for (i=0; i<(totalnumber); i++)
        {   for (n=0; n<((totalnumber)/4); n++)
            {   if (i==(0+(n*4)))
                {   if (array[i]==0)
                    {
                        array[i]=1;
                        break;
                    }
                }

                else if ((i==(3+(n*4))))
                {
                if (array[i]==0)
                {
                    array[i]=1;
                    break;
                }
                }
            }
        }
    }

Can you post the complete code?

Karthik Nishanth
– Karthik Nishanth

2016-11-13 15:46:43 +00:00
Commented Nov 13, 2016 at 15:46 — Karthik Nishanth
– Karthik Nishanth, Commented Nov 13, 2016 at 15:46

Community · Accepted Answer · 2017-05-23 12:13:40Z

2

Using a single break statement only breaks out of the nearest loop. It doesnt break out of the outer i loop. So, change your code to break out of the outer loop too.

One other way is to use both counter variables i,n within the same for loop. That means, you only use break once to break out of the outer for loop.

I quote from MSDN

Within nested statements, the break statement terminates only the do, for, switch, or while statement that immediately encloses it. You can use a return or goto statement to transfer control elsewhere out of the nested structure.

This is related - Can I use break to exit multiple nested for loops?

edited May 23, 2017 at 12:13

CommunityBot

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answered Nov 13, 2016 at 15:58

Karthik Nishanth

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