How to pass a braced-init-list to `std::array`’s constructor?

Is it possible to pass the exact braced-init-list to std::array’s constructor? This might be necessary since std::array does not support initializer list assignment.

Trying to adapt the accepted answer of this question: How to construct std::array object with initializer list? (answer’s shortened link: https://stackoverflow.com/a/6894191/4385532 ) to my problem, I came up with the following “solution” to the problem of passing a braced-init-list to the constructor of std::array:

template<class T, std::size_t N> struct ArrayWrapper
{
    std::array<T,N> arr;
    ArrayWrapper(T &&... init) : arr{{std::forward<T>(init)...}} {}
}

I was hoping that this would allow the following syntax:

int main()
{
  ArrayWrapper<int, 4> aw{{1,2,3,4}};
  std::cout << aw.arr[2] << '\n';
}

However, I failed. This won’t compile: http://ideone.com/VJVU1X

I’m not sure what is my error. I hoped that this line

ArrayWrapper(T &&... init) : arr{{std::forward<T>(init)...}} {}

would catch the exact elements of the braced-init-list passed to ArrayWrapper’s constructor, and forward them to the constructor of std::array.

What do I fail to understand?