Error in bash script switch case

Question

I want to create simple witch case in which I can execute functions based on user prompts:

echo Would you like us to perform the option: "(Y|N)"

read inPut

case $inPut in
# echoing a command encapsulated by
# backticks (``) executes the command
"Y") echo 'Starting.....'
donwload_source_code


# depending on the scenario, execute the other option
# or leave as default
"N") echo 'Stopping execution'
exit
esac

But when I execute the script I get error:

Would you like us to perform the option: (Y|N)
n
run.sh: line 27: syntax error near unexpected token `)'
run.sh: line 27: `"N") echo 'Stopping execution''
EMP-SOF-LT099:Genesis Plamen$

Dow you know how I can fix this issue?

You need to break case statements with ;;

123
– 123

2016-12-06 08:38:47 +00:00
Commented Dec 6, 2016 at 8:38 — 123
– 123, Commented Dec 6, 2016 at 8:38

Inian · Accepted Answer · 2016-12-06 08:44:29Z

2

Multiple issues.

Add a ;; at end of each case construct
The exit command is misplaced within the switch-case construct without the ;; present . It should be at the end of case or above.
read has a own option to print the message for user prompt, can avoid a unnecessary echo.

Error-free script

#!/bin/bash

read -p "Would you like us to perform the option: \"(Y|N)\" " inPut

case $inPut in
# echoing a command encapsulated by
# backticks (``) executes the command
"Y") echo 'Starting.....'
donwload_source_code
;;


# depending on the scenario, execute the other option
# or leave as default
"N") echo 'Stopping execution'
exit
;;

esac

answered Dec 6, 2016 at 8:44

Inian

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Comments

LF-DevJourney · Accepted Answer · 2016-12-06 08:40:14Z

2

add ;;

#!/bin/bash
echo Would you like us to perform the option: "(Y|N)"

read inPut

case $inPut in
# echoing a command encapsulated by
# backticks (``) executes the command
"Y") echo 'Starting.....'
donwload_source_code


# depending on the scenario, execute the other option
# or leave as default
;;
"N") echo 'Stopping execution'
exit
;;
esac

answered Dec 6, 2016 at 8:40

LF-DevJourney

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2 Comments

Peter Penzov Over a year ago

Thanks. I tested the code but the function is not called.

LF-DevJourney Over a year ago

for the bash doesnot know the donwload_source_code. You may have to define it.

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