I want to replace multiple same word in string with different words.
For example,
"What is your %s name and %s name"
I want to replace first '%s' with 'first' and second '%s' with 'last'.
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3 Answers
I think this might be cleaner:
['first', 'last'].forEach(function(tag) { x = x.replace('%s', tag); })
where x is the string you want to substitute into.
4 Comments
John Hascall
For a beginner like the OP I respectfully disagree.
rasmeister
Was the OP looking for an answer or an education?
Scott Weaver
how could this be simpler?
John Hascall
Well
['first','last'].forEach( tag => x = x.replace('%s', tag) ); would be "simpler", but one must walk before they run...If you use a string as the first arg to replace it only does 1 replace.
var s = "What is ... ";
var r = s.replace("%s", "first")
.replace("%s", "last");
More info here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace
Comments
You could use String#replace and use Array#shift as callback for replacing %s.
This solution uses shift, because it serves a value from the array for each call, if an item for replacement is found. Usually a string or a function is needed as second parameter for replace. This proposal uses shift with a binded array for replacement.
Function#bind returns a function with the binded object.
The
bind()method creates a new function that, when called, has its this keyword set to the provided value, with a given sequence of arguments preceding any provided when the new function is called.
var s = "What is your %s name and %s name?",
t = s.replace(/%s/g, [].shift.bind(['first', 'last']));
console.log(t);5 Comments
John Hascall
It wasn't me, but your answer could use some explanation of HOW this works. For starters how
func.bind() works... developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
Nina Scholz
@JohnHascall, maybe this is now better explained.
John Hascall
Better. Might also mention that
[].shift() is really Array.prototype.shift() because [] is an Array literal.Nina Scholz
i wrote it in the first line, with a link.
John Hascall
BTW, there is a similar 'fat arrow' approach:
t = s.replace(/%s/g, () => ['first', 'last'].shift() );