How to look for numbers that is between a range?
c = array[2,3,4,5,6]
>>> c>3
>>> array([False, False, True, True, True]
However, when I give c in between two numbers, it return error
>>> 2<c<5
>>> ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
The desire output is
array([False, True, True, False, False]
Try this,
(c > 2) & (c < 5)
Result
array([False, True, True, False, False], dtype=bool)
Python evaluates 2<c<5 as (2<c) and (c<5) which would be valid, except the and keyword doesn't work as we would want with numpy arrays. (It attempts to cast each array to a single boolean, and that behavior can't be overridden, as discussed here.) So for a vectorized and operation with numpy arrays you need to do this:
(2<c) & (c<5)
You can do something like this :
import numpy as np
c = np.array([2,3,4,5,6])
output = [(i and j) for i, j in zip(c>2, c<5)]
Output :
[False, True, True, False, False]
