Disable a link by adding a class and setting href with laravel blade

Question

I want to disable a link by adding a class and setting its href.

I came up with this but I am not happy with it.

    <a class="linkclass {!! $disabled ? 'disabled' : '" href="/page' !!}">Link</a>

So my questions are:

Is this a good practice? Do you recommend setting href by its condition of being disabled?
Which is the way you would suggest to do that?

What about the class? I want to set the class to disabled if the href is #. — llobet
– llobet, Commented Mar 2, 2017 at 14:08
I want to avoid the duplicity: if the link is active has href and no 'disabled' class, if it is disabled just the opposite. Taking this into account, is there any single condition solution? — llobet
– llobet, Commented Mar 2, 2017 at 14:22

online Thomas · Accepted Answer · 2017-03-02 14:31:06Z

1

if $disabled is a bool

@if($disabled)
    <a class="linkclass disabled">Link</a> // or optional <a class="linkclass disabled" href="#">Link</a>
@else
    <a class="linkclass" href="/link">Link</a>
@endif

but maybe it's better to have $disabled also contain the class string value "disabled" or empty.

<a class="linkclass {{$disabled}}"href="@if(isset($disabled))#@else /link @endif"></a>

answered Mar 2, 2017 at 14:31

online Thomas

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3 Comments

llobet Over a year ago

Ok @ThomasMoors, thanks for your answer, I assume maybe there is not a single condition solution. I suggest using ternary operator for the second solution <a class="linkclass {{$disabled}}" href="{{isset($disabled) ? '#' : '/link'}}"></a>

online Thomas Over a year ago

Why is this so bad in your opinion? This is at least escaped already, which is more secure. It also does not add a notable performance decrease at all, so what is the problem you have with this solution?

llobet Over a year ago

I don't think this is bad. Maybe it is a bad question! I was asking for a all-in-one solution like my first code.

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