How to find word location on string array in C++?

Question

for the program I'm writing I need to find the location of a specific word inside a string array, but I don't know how. This is the code I made but it doesn't work:

 int location;
 string input;

 cout << "Type your name" << endl;
 cin >> input;

  for (int i = 0; i <= count; i++) 
    {
        call_DB[i].name;

    if (call_DB[i].name == input)
        {
            location = i;
        }
    }

What is wrong with that code and what can I do to fix it? Thank you.

I don't think we have enough information to answer this question. Try examining the contents of call_DB[...] in your debugger, watching for whitespace. It may also be worthwhile to store your strings in some STL container like an std::set, std::unordered_set or std::map for quick ((O)log(N) or even (O)1 rather than (O)N) lookup times. — JeremiahB
– JeremiahB, Commented Mar 22, 2017 at 3:28

Chen OT · Accepted Answer · 2017-03-22 03:29:17Z

1

Try std::find_if, which searches the array for item satisfying provided predict function.

auto iter = std::find_if(call_DB, call_DB + count, [&input](const YOUR_CALL_DB_TYPE& item ){ return item.name == input; });

if(iter == call_DB + count) 
     printf("Not found\n");
else
     printf("Found: %s\n", iter->name.c_str());

If such item is found, the index is the distance from array base, size_t index = iter - call_DB;

answered Mar 22, 2017 at 3:29

Chen OT

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Joseph Thomson · Accepted Answer · 2017-03-22 10:00:15Z

1

You can get an iterator to the array element using std::find_if:

auto it = std::find_if(std::begin(db), std::end(db), [&name](auto const& x) {
  return x.name == name;
});

And if you want the index into the array:

auto index = it - std::begin(db);

edited Mar 22, 2017 at 10:00

answered Mar 22, 2017 at 7:43

Joseph Thomson

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