Get int user input in java using delimiters and hasNext?

Question

public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    in.useDelimiter(", "); // using delimiter ", "

    int i = 1;
    while(in.hasNextInt()){
        i = in.nextInt();
        System.out.println(i);
    }
}

I am trying to get the input from console, but this code is not printing last integer How can I solve this problem. I don't want to use split and save the result in an array.

csirmazbendeguz · Accepted Answer · 2017-03-28 22:39:39Z

2

You will need to use a regex pattern.

in.useDelimiter(",?\\s");

OR, if it is not necessarily seperated by both spaces and commas (e.g. 1, 4,5465, 5):

in.useDelimiter("[,\\s]+"); // this is more permissive

edited Mar 28, 2017 at 22:39

answered Mar 28, 2017 at 22:15

csirmazbendeguz

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2 Comments

void Over a year ago

You tried a wrong pattern, it will not use "," as delimiter i.e try 1, 4,5465, 5 as input, you'll get 1,4,5,4,6,5,5 as output

csirmazbendeguz Over a year ago

@negia Yeah, I realized that just now, I removed the * (damn! it didn't go unnoticed :)).

void · Accepted Answer · 2017-03-28 22:16:21Z

0

With Scanner.useDelimiter, the string after your last input integer should match the delimiter pattern, for example with your pattern if you give "1, 3, 5, 6, " you will get 1 3 5 6 as output but if you give "1, 3, 5, 6" you will not get the last integer.

answered Mar 28, 2017 at 22:16

void

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