Regex remove character from capturing group/workaround

Question

Suppose I have a String like following

@ABCD|NN12CT55|GFR

now I want to match

@ABCD|N

and replace it with

@ABCD N

regex for matching @ABCD\|[^G]

is there a way to remove the | from the capturing group?

@AvinashRaj its working for the given example, but i cant seem to adapt it into my needs. can you give me an solution for this? @ABCD|NN12CT55|GFR is input. and maybe a little explanation what it does? — XtremeBaumer
– XtremeBaumer, Commented Apr 6, 2017 at 11:53
Please update the question to show the real life scenario and explain what is wrong with your regex. You do not even have a capturing group in your regex, why do you ask how to remove a char from a capturing group? Perhaps, you need to use one. Like in (@ABCD)\|(?!G). Or (@ABCD)\|([^G]). — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Apr 6, 2017 at 11:55
@WiktorStribiżew i know that i can repplace with $0 which matches the exact value from what the regex matches, but i dont want the | in it — XtremeBaumer
– XtremeBaumer, Commented Apr 6, 2017 at 12:06

Mustofa Rizwan · Accepted Answer · 2017-04-06 12:01:30Z

5

You can try this regex

^@[^|]*\K\|

and replace by:

" "

Explanation:

^ marks start of a string
@ matches @ sign
[^|]* matches anything but not pipe |
\K if match being found upto previous point, then \K makes the current position as starting point therefore the previous part wont be replaced
\| matches the pipe --> this pipe is going to be replaced

Demo

answered Apr 6, 2017 at 12:01

Mustofa Rizwan

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5 Comments

XtremeBaumer Over a year ago

so \K always sets the new "start" of the match if it finds something which is not | and once the | occurs it stops resetting the start?

Mustofa Rizwan Over a year ago

\K forgets about the past matches and marks the current position as match... as everything upto \K were to find everything but not | , therefore we need to forget about everything that we don't need to replace. \K does this. From there on the next character is | thus it gets matched. and all match thing is going to be replaced by " " i.e empty space

XtremeBaumer Over a year ago

and how come it only matches the first pipe? is it because of ^?

Mustofa Rizwan Over a year ago

let's first forget about \K, ^[^|]* means match everything which is not pipe from the initial point so it will match everything until |, as we know , thus I put a pipe | immediately to be matched and it get matched ... and i totally don't bother what comes after that matched | and don't even match anything

Okto Over a year ago

How can I use this with JavaScript API for Regular Expressions? I have watched your demo and it worked, but when I use it with JavaScript, then it always returns null! For example: var word = '@ABCD|NN12CT55|GFR'; let matchresult = word.match(/^@[^|]*\K\|/gm); console.log(matchresult) I tried exec, match, etc... but didnt work!

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