Split string/variable on first occurrence delimiter (UNIX)

Question

I would like to split the string with delimiter. variable my_string contains Hello_This_Is_My_string The output will be only

Below is my code :

result = $(echo $my_string |" cut -d '_' -f2")

However, I am getting <Is> instead of <This_Is_My_string>

GMartinez · Accepted Answer · 2019-04-02 00:37:27Z

10

I have found an answer:

result=$(echo $my_string | cut -d "_" -f 2-)

Test with:

echo aa_bb_cc | cut -d "_" -f 2-

GMartinez

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answered Apr 13, 2017 at 3:30

Jolin

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4 Comments

If it works and is the answer, mark it as answer. Others may find it useful.

I cant mark the answer as there is a prompt said "You can accept your own answer in 2 days"

I do not understand your quotes. Use result=$(echo $my_string | cut -d "_" -f 2-).

@WalterA to cut the string with a delimiter "_"

ULick · Accepted Answer · 2017-04-16 10:04:36Z

2

Avoid calling external commands, do it with shell-internal 'Parameter Expansion', which has quite powerfull options

my_string='Hello_This_Is_My_string'
echo "result = ${my_string#*_}"

answered Apr 16, 2017 at 10:04

ULick

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