I have a text file which have multiple urls with detail paths i want to get only base urls using regex
Text file contain urls like this
www.facbook.com/abc/xyz
www.google.com.pk/q=12hsjak
www.yahoo.co.uk/avga/ajak
defence.pk/zya/bahawalpur
Pic2fly.uk/abc
Want output like this
Www.facebook.com
Www.google.com.pk
Www.yahoo.co.uk
Defence.pk
Pic2fly.uk
Please help
I have tried this
Print re.search(r'(https?://)?(www\.)?([^/]*)', url)[3]
You don't really need re for this, try os.path.split or urlparse.
os.path.split. That's the wrong tool for the job, even if it works on some/most/all operating systems.I would keep all URLs with ('/') inside, into a list, then would search the list like this:
list1=['www.facbook.com/abc/xyz','www.google.com.pk/q=12hsjak','www.yahoo.co.uk/avga/ajak','defence.pk/zya/bahawalpur','Pic2fly.uk/abc']
i=0
while i<len(list1):
print(list1[i][:list1[i].find('/')])
i+=1
result is what you want, like this:
www.facbook.com
www.google.com.pk
www.yahoo.co.uk
defence.pk
Pic2fly.uk
