Is there a way to make SQLAlchemy generate a query with a custom column that is a subquery that correlates with current row:
SELECT
tab1.id,
tab1.col1,
...,
(
SELECT count(1) FROM tab2
WHERE tab2.tab1_id = tab1.id
GROUP BY tab2.col1
) as cnt
FROM tab1
WHERE ...
LIMIT 100
using the ORM API?
session.query(Tab1, ?(subquery for additional column)?).filter(...).limit(100)
I'm using PostgreSQL 9.3 and old version of SQLAlchemy 0.9.8
If you need this often, and/or the count is an integral part of your Tab1 model, you should use a hybrid property such as described in the other answer. If on the other hand you need this just for a single query, then you could just create the scalar subquery using Query.label(), or Query.as_scalar():
count_stmt = session.query(func.count(1)).\
filter(Tab2.tab1_id == Tab1.id).\
group_by(Tab2.col1).\
label('cnt')
session.query(Tab1, count_stmt).filter(...).limit(100)
The subquery will automatically correlate what it can from the enclosing query.
as_scalar is deprecated in 1.4 and should be replaced with scalar_subquery.You can do this, but it works in a quite different way to how you have written it. You can create a property of Tab1 which depends on the relationship to tab2 (assuming that tab2.tab1_id is a foreign key, which it should be.
Your models look like this:
class Parent(Base):
__tablename__ = 'parent'
id = Column(Integer, primary_key=True)
children = relationship("Child")
class Child(Base):
__tablename__ = 'child'
id = Column(Integer, primary_key=True)
parent_id = Column(Integer, ForeignKey('parent.id'))
as per the docs on relationships
Then you can add something like
@hybrid_property
def number_of_children(self):
if self.children:
return len(self.children)
return 0
@number_of_children.expression
def number_of_children(cls):
return (select([func.count(Child.id)])
.where(Child.cover_id == cls.id))
to the Parent model, as per this answer and more docs.
Once you've done this, you can filter on this property the same as any other column-based one.
Simply define a select statement for your sub-query statement. You can then use it as a column in another select statement.
Using Ilja Everilä's example:
count_stmt = (select(func.count(1))
.where(Tab2.tab1_id == Tab1.id)
.group_by(Tab2.col1)
.scalar_subquery()
.label('cnt'))
More details are in the SQLAlchemy 2.0 documentation.
