regex to remove characters at end of word only - js

Question

I am trying to remove exclamation marks at the end of a word.

eg. remove("!!!Hi !!hi!!! !hi") === "!!!Hi !!hi !hi"

I am able to remove all exclamation marks, but am unable to target those just at the end of a word.

The following is what I currently have.

function remove(s){
  return s.replace(/([a-z]+)[!]/ig, '$1');
}

I think you may use .replace(/\b!+\B/g, '')

Wiktor Stribiżew
– Wiktor Stribiżew

2017-07-26 07:43:51 +00:00
Commented Jul 26, 2017 at 7:43 — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 26, 2017 at 7:43

techfoobar · Accepted Answer · 2017-07-26 07:37:36Z

1

You can strip off !s that are at the end of words using the following RegExp:

"!!!Hi !!hi!!! !hi"
  .replace(/!+\s/g, ' ')  // this removes it from end of words
  .replace(/!+$/g, '')    // this removes it from the end of the last word

Result: "!!!Hi !!hi !hi"

answered Jul 26, 2017 at 7:37

techfoobar

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Comments

Egan Wolf · Accepted Answer · 2017-07-26 08:20:10Z

1

You cant try this one:

\b!+

It matches ! that follows a word.

edited Jul 26, 2017 at 8:20

answered Jul 26, 2017 at 7:44

Egan Wolf

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Comments

idmean · Accepted Answer · 2017-07-26 07:38:48Z

0

Change your regex to:

/([a-z]+)!+/ig

Then

function remove(s){
  return s.replace(/([a-z]+)!+/ig, '$1');
}

should work

answered Jul 26, 2017 at 7:38

idmean

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Comments

Lalit Sachdeva · Accepted Answer · 2017-07-26 07:42:29Z

0

you can use this regex

console.log("!!!Hi !!hi!!! !hi!!!".replace(/([a-z]+)[!]+/ig, '$1'))

answered Jul 26, 2017 at 7:42

Lalit Sachdeva

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1 Comment

Wiktor Stribiżew Over a year ago

This is a copy of @idmean's answer with no added value.

Mikkel Bachmann · Accepted Answer · 2017-07-26 07:52:42Z

0

I think it will be easier not to use regex, but insted use lastIndexOf and slice

something like:

function removeQuestionmark(inputvalue) {
  var index = inputValue.lastIndexOf("!");

  if(inputValue.endsWith("!"))
    return inputvalue.slice(0,index-1);

  return `${inputvalue.slice(0,index-1)${inputValue.slice(index+1)}}
}

I have not tested the code.

answered Jul 26, 2017 at 7:52

Mikkel Bachmann

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Comments

MrHutnik · Accepted Answer · 2017-07-26 08:05:27Z

0

Well you should add a + so you take more than one !

function remove(s){

    return s.replace(/([a-z]+)([!]+)/ig, "$1");
}

answered Jul 26, 2017 at 8:05

MrHutnik

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