Is there a way to initialize arrays with mixed chars and "strings"

Question

I would want to initialize char array during compilation time with least amount of manual work.

Is there a working shorthand format for this

char arr[5] = {0x4, 'a', 's', 'd' 'c'};

such as

char arr[5] = {0x4, "asdc"};

Isn't this an XY problem? Why would you want to have that arr? Shouldn't it be const if you want to initialize it at compile time? — Walter
– Walter, Commented Aug 2, 2017 at 11:42

score 1 · Accepted Answer · 2017-08-02 12:09:32Z

1

You could integrate the char int the string with escape sequences:

char arr[6] = { "\x04asdc"};

edit: corrected the wrog length of the array.

edited Aug 2, 2017 at 12:09

answered Aug 2, 2017 at 11:36

user2672107

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2 Comments

Some programmer dude Over a year ago

The problem with this is that the string "\x04asdc" is six characters long. Specifying a to small array size is incorrect.

Quentin Over a year ago

@Someprogrammerdude please disregard my previous comments, I accidentally ended up on a C page. The nul-terminator is indeed explicitly mandated in C++.

Some programmer dude · Accepted Answer · 2017-08-02 11:37:11Z

1

No that's not possible. But you could do

char arr[] = "\04asdc";

The problem with this is that is would not be exactly like the original array you show, since it would include the string terminator and therefore have six elements.

answered Aug 2, 2017 at 11:37

Some programmer dude

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