Java get specific value from list and add to other list

Question

i want to ask some question, how to get specific value from list and add to another list, lets say i have list (this is cust list from hibernate DAO) like:

[["marketplace","001-002-003"],["insurance","142-523-132"],["car purchase","982349824"]]

i just want to get a value of "marketplace","insurance", and "car purchase" from that list and add to new list called "bu"

here is my code

public @ResponseBody String findBU(@RequestBody AllCustomerHist customer){
        BigDecimal id= customer.getId();
        String message;
        List<String> bu= new ArrayList<>();
        int i;

        System.out.println("ID = "+id);
        List<AllCustomerHist> cust = allCustomerHistService.findBU(id);


        for (i=0; i<cust.size(); i++){
            System.out.println("iteration = "+i);

            // stumbled here //
        }

        JSONObject json = new JSONObject();
        json.put("id", id);
        json.put("BU", bu);

        message = json.toString();
        return message;

    }

this is my AllCustomerHistDaoImpl class

//release 1.3
@SuppressWarnings("unchecked")
public List<AllCustomerHist> findBU(BigDecimal adpId) {
    // TODO cek kodingan
    Criteria criteria = getSession().createCriteria(AllCustomerHist.class)
            .setProjection(Projections.projectionList()
                    .add(Projections.property("srctable"), "srctable")
                    .add(Projections.property("customerId"), "customerId"))
    .add(Restrictions.eq("adpId", adpId));

    return (List<AllCustomerHist>)criteria.list();
}

Notice that AllCustomerHist is an entity class to define the table in hibernate

thank you for your helps :D

What's the structure of AllCustomerHist? More importantly, why do assume we would know? — shmosel
– shmosel, Commented Aug 25, 2017 at 3:14
You have shown the cust list from Hibernate in a way it looks like a Map. Then you're using a list with AllCustomerHist type elements. It seems it's not compatible. — Paulo Pedroso
– Paulo Pedroso, Commented Aug 25, 2017 at 3:18
@PauloPedroso the result of cust is not a pair of key:value, its result set from 2 column, first is srctable column ("marketplace, insurance, car purchase" is come from here) and the second is from customerID column — galih
– galih, Commented Aug 25, 2017 at 3:26

Angelo Immediata · Accepted Answer · 2017-08-25 06:01:53Z

1

Since you need to make some validation and you need to take off the whole AllCustomerHistobject what I would do is the following code

List<AllCustomerHist> cust = allCustomerHistService.findBU(id);
List<String> bu = new ArrayList<String>(cust.size());

        for (i=0; i<cust.size(); i++){
            System.out.println("iteration = "+i);
            AllCustomerHist aCust = cust.get(i);
            bu.add(aCust.getSrctable());

        }
//here your bu list should be ready to be used.....

I hope it's what you needed

answered Aug 25, 2017 at 6:01

Angelo Immediata

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2 Comments

galih Over a year ago

it cannot casted from object to allcustomerhist, your code is correct, but i need to transform my resultset using setResultTransformer(Transformers.aliasToBean(AllCustomerHis‌t.class))

Angelo Immediata Over a year ago

Ah so the AllCustomerHist was not the entity class.... I understood it was the entity class otherwise I would have told you to use the hibernate transformer. Anyway I'm glad it works

Robyn Liu · Accepted Answer · 2017-08-25 10:26:32Z

0

If you use JDK1.8+, you can also do it like this:

List<AllCustomerHist> cust = allCustomerHistService.findBU(id);
List<String> bu = cust.stream()
    .map(AllCustomerHist::getSrctable)
    .collect(Collectors.toList());

answered Aug 25, 2017 at 10:26

Robyn Liu

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