scala 2.11.8 how to fill an array

Question

I want to create an array that contains the same value repeated for a very large number of times, say 1,000,000.

I was thinking to use something like Array.fill(1000000)(0). However, after reading the documentation for Scala 2.11.8, I found that there is no such members of Array in this version.

Is there any other ways that can create the array without using loop? Thanks in advance for your help.

Have your tried fill yourself? The fill method already existed in scala 2.11.8. — Eastsun
– Eastsun, Commented Sep 3, 2017 at 5:05

rennerj2 · Accepted Answer · 2018-08-01 11:28:57Z

5

This will do the trick:

Array.fill[Int](1000000)(0)

Read more here: https://alvinalexander.com/scala/scala-list-class-examples

edited Aug 1, 2018 at 11:28

rennerj2

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answered Sep 3, 2017 at 17:16

Sohum Sachdev

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Ra Ka · Accepted Answer · 2017-09-03 02:03:21Z

1

You can use range to iterate through required length (1000000 times in your case) and then return a default value which is 0 in each iteration as below.

val arr:Array[Int] = (1 to 1000000 map(_ => 0)).toArray

answered Sep 3, 2017 at 2:03

Ra Ka

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Dima · Accepted Answer · 2017-09-03 01:32:09Z

1

Stream.continually(0).take(1000000).toArray would do that .. but why in the world would you want something like this???

answered Sep 3, 2017 at 1:32

Dima

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