How to split an already split array ruby

Question

I have this function in Ruby

def translate word  
  vowels=["a","e","I","O","U"]  
  i=1.to_i
  sentense=word.split(" ").to_a     
  puts sentense if sentense.length >=1
  sentense.split("")        
  puts sentense     
end

I have this phrase "this is a test phrase " and at first I want to create an array that looks like:

["this","is","a", "test", "phrase"]

Then I want to create another array it to look like: [["t","h","i","s"],["i","s"],["a"],["t","e","s","t"],["p","h","r","a","s","e"].

I tried

sentense=word.split(" ").to_a
new_array=sentense.split("").to_a

but it didn't work

"but it didn't work" - of course. You'll need to call split on individual elements. — Sergio Tulentsev
– Sergio Tulentsev, Commented Sep 20, 2017 at 15:06

Sebastián Palma · Accepted Answer · 2017-09-20 15:28:49Z

6

You could use String#split, Enumerable#map and String#chars:

p "this is a test phrase".split.map(&:chars)
# => [["t", "h", "i", "s"], ["i", "s"], ["a"], ["t", "e", "s", "t"], ["p", "h", "r", "a", "s", "e"]]

string.split(' ') could be written as string.split, so you can omit passing the whitespace in parenthesis.

And this also gives you an array, there's no need to use to_a, you'll have an array like ["this", "is", "a", "test", "phrase"], so you can use map to get a new array and for each element inside an array of its characters by using .split('') or .chars.

edited Sep 20, 2017 at 15:28

answered Sep 20, 2017 at 15:07

Sebastián Palma

33.6k6 gold badges45 silver badges65 bronze badges

Sign up to request clarification or add additional context in comments.

6 Comments

Stefan Over a year ago

You don't mention map in your explanation, although it's the essential part.

Sebastián Palma Over a year ago

Sorry, now yes @Stefan.

Charalambos Pouroutides Over a year ago

I did this way because i the phrase will change but i get an undefined method for split def translate word sentense=word.split sentense.split.map(&:chars) puts split end translate("I have this phrase")

Sebastián Palma Over a year ago

You're using split as a variable, but you haven't defined it @CharalambosPouroutides. And the second split isn't needed if you've initialized sentences as word.split, try def translate word; sentense = word.split; sentense.map(&:chars); end; p translate("I have this phrase").

Stefan Over a year ago

@CharalambosPouroutides you can omit the temporary variable and simply write word.split.map(&:chars)

|

Cary Swoveland · Accepted Answer · 2017-09-20 19:53:21Z

1

def chop_up(str)
  str.strip.each_char.with_object([[]]) { |c,a| c == ' ' ? (a << []) : a.last << c }
end

chop_up "fee fi fo fum"
  #=> [["f", "e", "e"], ["f", "i"], ["f", "o"], ["f", "u", "m"]]
chop_up " fee fi fo fum "
  #=> [["f", "e", "e"], ["f", "i"], ["f", "o"], ["f", "u", "m"]]
chop_up "feefifofum "
  #=> [["f", "e", "e", "f", "i", "f", "o", "f", "u", "m"]]
chop_up ""
  #=> [[]]

answered Sep 20, 2017 at 19:53

Cary Swoveland

111k6 gold badges69 silver badges105 bronze badges

1 Comment

Cary Swoveland Over a year ago

I would use @Sebastián's answer, but thought mine might be of interest.

Collectives™ on Stack Overflow

How to split an already split array ruby

2 Answers 2

6 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

6 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related