How to use a php variable inside preg_match? [duplicate]

Question

$pId = "MP000000001648426";

Below code is not working. Whats wrong with it?

preg_match_all('/<span id="price_$pId".*?>(.*?)\<\/span>/', $product ,$matches);

But, when I directly add the string (pId) to preg_match it works.

preg_match_all('/<span id="price_MP000000001648426".*?>(.*?)\<\/span>/', $product ,$matches);

But I want to provide a variable inside the preg match. How to do it?

Use double quotes. You can't interpolate variables inside single quoted string literals. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Oct 3, 2017 at 11:27
@WiktorStribiżew That solved the issue, Post-it as the answer — Anoop Mayampilly Muraleedharan
– Anoop Mayampilly Muraleedharan, Commented Oct 3, 2017 at 11:30
This is a dupe of too many questions, no need to post an answer. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Oct 3, 2017 at 11:31

jens1o · Accepted Answer · 2017-10-03 11:29:22Z

1

change it to

preg_match_all("/<span id=\"price_$pId\".*?>(.*?)\<\/span>/", $product, $matches);

(note that you need real " so that PHP Variables are converted)

Alternative solution:

preg_match_all('/<span id="price_'. $pId . '".*?>(.*?)\<\/span>/', $product, $matches);

answered Oct 3, 2017 at 11:29

jens1o

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1 Comment

user1614753 Over a year ago

For some reason the alternative solution doesn't work me! I don't like using double quotes for text in PHP, therefore I prefer to concat single quoted text with vars using the dot symbol. But last time I tried this, preg_match literally searched for the single quote character as part of the pattern!!! This was my code...

preg_match_all('/[^' . $tron->separator . ']+' . $tron->separator . '[^' . $tron->separator . ']+/u', $tron->getAkas(), $outer);

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