Make $ docker compose a command for docker-compose

Question

Is there a way to have docker compose run docker-compose in a bash alias?

I know docker is a command of it's own so I don't think you can, I thought I would ask since it drive's me nuts making aliases when I type docker so much.

i already have alias dco=docker-compose but you know, a brother is looking for a better way. :)

Why not make your own docker command that calls the real docker or docker-compose based on the args? — BMitch
– BMitch, Commented Nov 9, 2017 at 15:36
Alias are just straight-up text replacement; alias dco='docker compose' would work. — chepner
– chepner, Commented Nov 9, 2017 at 15:40
Or are you looking for a way to parameterize the alias, so that one alias covers multiple subcommands? For that, you need to use a function: something like d () { if [[ $1 = com* ]]; then docker compose "${@:2}"; elif ... fi; }, which would let you run d co to run docker compose. — chepner
– chepner, Commented Nov 9, 2017 at 15:42
See similar question: stackoverflow.com/questions/34748747/… — Zlemini
– Zlemini, Commented Nov 9, 2017 at 16:14
@chepner and if we want to bash autocomplete work with dco like with docker-compose, we can add little workaround. First step, find complete config string with complete | grep docker-compose. Second, change found string from complete -F _docker_compose docker-compose to complete -F _docker_compose dco and save it to the file ~/.bash_completion. Now I got any subcommand expand with <Tab> :) — Denys Synashko
– Denys Synashko, Commented Dec 12, 2017 at 22:07

marcolz · Accepted Answer · 2017-11-09 16:23:06Z

4

You could make a function instead:

docker() {
  if [ "$1" = "compose" ]
  then
    shift
    docker-compose "$@"
  else
    command docker "$@"
  fi
}

Here the command prevents the docker function from calling itself again.

See also: Can I alias a subcommand? (shortening the output of `docker ps`) as commented by @zlemini

edited Nov 9, 2017 at 16:23

answered Nov 9, 2017 at 15:42

marcolz

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