Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine();
System.out.println(input);
int a = Integer.parseInt(input.substring(2), 16);
System.out.println(Integer.toBinaryString(a));
Above mentioned code that takes in hex value and convert it into binary. However, this would not work on input "0xBE400000" but it works fine for "0x41C20000"
BE400000 is larger than Integer.MAX_VALUE (whose hex representation is 7FFFFFFF).
Therefore you'll need to parse it with
long a = Long.parseLong(input.substring(2), 16);
Long isn't big enough, go to BigInteger/BigDecimalSince 0xBE400000 is in the range of an unsigned int you can use: parseUnsignedInt(String s, int radix)
int a = Integer.parseUnsignedInt(input.substring(2), 16);
With parseUnsignedInt(input, 16) you can parse values from 0x00000000 to 0xFFFFFFFF, where:
You can use Long
long l = Long.parseLong(input.substring(2), 16);
but if your value is greater than 2^63 - 1 you may use use a BigInteger's constructor:
BigInteger(String val, int radix) Translates the String representation of a BigInteger in the specified radix into a BigInteger.
BigInteger b = new BigInteger(input.substring(2), 16);
