Return an element in array if condition is met

Question

Given this array:

[[{"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[]}],
[{"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}],
[{"RepCode"=>"ABCD", "ID"=>"637e9117-ed03-45ef-8950-a234902038", "Name"=>"Sarah, Barber", "Folios" => [{"ID"=>"46aafe31-f686-49e2-9d58-c694ea55c14f"}]]

I need to return the ONE array that matches the given id for the Folio key

CODE:

correct_manager = managers.detect do |manager|
  manager.first["Folios"].map { |f| f["ID"] == "d0cda2be-c142-47d1-9a81-a76c0eea2765" }
end

That returns:

{"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[]}

And I want it to return

{"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}

because the ID's match in the detect method.

How can I return the one array that matches the passed in id?

Your array seems to be bad formatted.

Sebastián Palma
– Sebastián Palma

2018-03-30 21:46:08 +00:00
Commented Mar 30, 2018 at 21:46 — Sebastián Palma
– Sebastián Palma, Commented Mar 30, 2018 at 21:46
Do the Folios arrays ever contain more than one Folio?

Nathan
– Nathan

2018-03-30 22:03:59 +00:00
Commented Mar 30, 2018 at 22:03 — Nathan
– Nathan, Commented Mar 30, 2018 at 22:03

Nermin · Accepted Answer · 2018-03-30 21:49:50Z

2

You can use Enumerable #find

correct_manager = managers.find do |manager|
  folios = manager.first["Folios"][0] || {}
  folios["ID"] == "d0cda2be-c142-47d1-9a81-a76c0eea2765"
end

answered Mar 30, 2018 at 21:49

Nermin

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Comments

lacostenycoder · Accepted Answer · 2018-03-31 21:00:47Z

1

First let's format your data correctly:

managers =  [
  [ {"RepCode"=>"AL20", "ID"=>"eae71dff-3796-4c61-956e-a75a00b01a7b", "Name"=>"Schuh, Eddy", "Folios"=>[] } ],
  [ {"RepCode"=>"ABNX", "ID"=>"637e9117-ed03-45ef-8950-a7220087ee9a", "Name"=>"Eckerson, Kathy", "Folios" => [{"ID"=>"d0cda2be-c142-47d1-9a81-a76c0eea2765"}] } ],
  [ {"RepCode"=>"ABCD", "ID"=>"637e9117-ed03-45ef-8950-a234902038", "Name"=>"Sarah, Barber", "Folios" => [{"ID"=>"46aafe31-f686-49e2-9d58-c694ea55c14f"}] } ] 
]

target_id = 'd0cda2be-c142-47d1-9a81-a76c0eea2765'

managers.flatten.find{|k,_v| k['Folios'].any?{|f| f.key?('ID') && f['ID'] == target_id}}

edited Mar 31, 2018 at 21:00

answered Mar 31, 2018 at 6:37

lacostenycoder

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Comments

Cary Swoveland · Accepted Answer · 2018-03-31 21:11:03Z

1

def doit(managers, val)
  managers.find { |(h)| h["Folios"] == ["ID"=>val] }
end

managers = [
  [{ "RepCode"=>"AL20", "Folios"=>[] }],
  [{ "RepCode"=>"ABNX", "Folios"=>[{ "ID"=>"d0cda2be-c142-47d1-9a81" }] }],
  [{ "RepCode"=>"ABCD", "Folios"=>[{ "ID"=>"46aafe31-f686-49e2-9d58" }] }]
]

doit(managers, "d0cda2be-c142-47d1-9a81")
  # => [{"RepCode"=>"ABNX", "Folios"=>[{"ID"=>"d0cda2be-c142-47d1-9a81"}]}]

edited Mar 31, 2018 at 21:11

answered Mar 31, 2018 at 1:54

Cary Swoveland

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