Java catch different exceptions

Question

public class ExceptionHandler {

    public static void main(String[] args) throws FileNotFoundException, IOException {
    // write your code here
        try {
            testException(-5);
            testException(11);
        } catch (FileNotFoundException e){
            System.out.println("No File Found");
        } catch (IOException e){
            System.out.println("IO Error occurred");
        } finally { //The finally block always executes when the try block exits.
            System.out.println("Releasing resources");
            testException(15);
        }
    }

    public static void testException(int i) throws FileNotFoundException, IOException {
        if (i < 0) {
            FileNotFoundException myException = new FileNotFoundException();
            throw myException;
        }
        else if (i > 10) {
            throw new IOException();
        }
    }
}

The output of this code gives

No File Found Releasing resources

Is it possible to have java catch both IOException as well as FileNotFoundException? It seems to be only able to catch the first exception and doesn't catch the IOException

It's possible, but not that way. You would have to nest the first try/catch in another try block, and to rethrow the FileNotFoundException from the nested catch block. But why would you do that? Just do the same thing in both catch blocks if that's what you want. — JB Nizet
– JB Nizet, Commented Apr 7, 2018 at 9:05
first "testException(10);" line never execute as per your code — Amit Bera
– Amit Bera, Commented Apr 7, 2018 at 9:08
This is a tricky code example that contains several conditions not as easy to see as it seems. I guess that executing it will show in the standard output an exception not being captured (you should have shown it in your question). See my answer to understand what is happening. — Paco Abato
– Paco Abato, Commented Apr 7, 2018 at 10:02

Matei Radu · Accepted Answer · 2018-04-07 09:06:30Z

3

The try block stops at the first exception thrown, therefore the second call of testException() is never executed.

answered Apr 7, 2018 at 9:06

Matei Radu

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6 Comments

Paco Abato Over a year ago

The second call to testException() is indeed testException(15); and it is actually being executed (see my answer which explains it).

Matei Radu Over a year ago

I'm referring to the second one in the try block.

Paco Abato Over a year ago

I know, but that call to testException does not throw the IOException anyway (because 10 is not > 10). So that is not the problem of Eneres.

Matei Radu Over a year ago

What you say is true but this is also the problem, because even if the second call would satisfy the condition to throw a FileNotFoundException it would never be called because of the exception thrown by the first call in the try block.

Paco Abato Over a year ago

It depends on the intention of the programmer. Hopefully he will explain to us :)

|

Paco Abato · Accepted Answer · 2018-04-08 07:08:16Z

2

You should enclose your try/catch/finally block inside another try/catch block because your finally block can throw exceptions that must be captured.

Here is how your code works:

testException(-5) throws a FileNotFoundException
FileNotFoundExceptionis catched by catch (FileNotFoundException e)
No File Found is printed into the standard output
Then finally block is executed (the testException(10) sentence is not executed).
So Releasing resources is printed
And testException(15) is executed throwing an IOException that is not captured anyway (the program will be interrupted).

If you remove the throws FileNotFoundException, IOException from your main method the compiler will alert you that an exception is not being captured (the one in the finally block).

edited Apr 8, 2018 at 7:08

answered Apr 7, 2018 at 9:32

Paco Abato

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