How to ESCAPE "comma" in Javascript

Question

EDIT1:

btnDelete.Attributes.Add("onclick", String.Format(@"return DeleteRow('{0}',{1},{2},{3});", e.Row.ClientID, e.Row.RowIndex, DataBinder.Eval(e.Row.DataItem, "Id"), "'" + DataBinder.Eval(e.Row.DataItem, "Name") + "'"));

edit:

i get this error:

Message: Unterminated string constant

i am passing the value from code behind and some of my text have somethinh lke this:

Foo3, In.c

   //javascript
    function DeleteRow(rowId, rowIdx, Id, Name) {         
        var textForMessage = "return confirm('Are you sure you want to delete this record with the name: \n{0} \n{1}');";
        //removed code...  
       return result;
    }

Your code looks... strange. You define parameters which you don't use. You initialize a local variable which you don't use. And you return a variable which you have not defined... If the text you have is Foo3, In.c then where is this value passed? Even if it is passed as one of the parameters, you are not doing anything with them... Please provide a more complete/correct/whatever example. — Felix Kling
– Felix Kling, Commented Feb 14, 2011 at 21:50
But you've also removed any indication of an actual issue. Please post full code that demonstrates the issue, not merely the part that you assume represents whatever issue you're having. In other words, please provide a working example. — user113716
– user113716, Commented Feb 14, 2011 at 22:04

Quentin · Accepted Answer · 2011-02-14 21:46:06Z

10

Do nothing. A comma has no special meaning inside a JavaScript string.

answered Feb 14, 2011 at 21:46

Quentin

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1 Comment

joe.liedtke Over a year ago

Yup, you would want to escape single quotes though. You can escape single quotes with a "\" ... so ' becomes \' in the javascript that you emit.

Mark Byers · Accepted Answer · 2011-02-14 21:52:18Z

2

You don't need to escape the comma. You should surround the entire string with quotes:

'Foo3, In.c'

If this string is inside another string which is also single-quoted you may need to escape the quotes.

edited Feb 14, 2011 at 21:52

answered Feb 14, 2011 at 21:46

Mark Byers

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1 Comment

Nick Kahn Over a year ago

i have updated my question, i am passing the name with surround with single quotes.

user447356 · Accepted Answer · 2011-02-14 22:21:00Z

0

If the error is client side you can solve it by having:

btnDelete.Attributes["onclick"] = String.Format("return DeleteRow('{0}', '{1}', '{2}', '{3}');", e.Row.ClientID, e.Row.RowIndex, DataBinder.Eval(e.Row.DataItem, "Id"), DataBinder.Eval(e.Row.DataItem, "Name").ToString().Replace("'", "\'"));

If it's server side, please post the full error message plus stack trace.

answered Feb 14, 2011 at 22:21

user447356

2 Comments

Nick Kahn Over a year ago

yes the error is at client side and if i comment the server side line code which is (btnDelete ....... ) than it works fine without any javascript error, but if uncomment the server side code than i do see the error ` Message: Unterminated string constant `

user447356 Over a year ago

@Abu did you try with the exact line I posted instead of the line you have?

Rory McCrossan · Accepted Answer · 2015-09-25 15:19:39Z

0

\x2c

Useful in ajax.

function myfunction(id, str_URL) {
     $.ajax({
         type: "GET",
         url: str_URL,
         success: function(t) {
             var link = "<a href=\x22JavaScript:MyJava(\x22Param1\x22\x2c\x22Param2\x22)\x22>Link text</a>";
         }

     });
}

\x22 is " (quote)

Just reference the Hex column in the ascii table.

http://www.asciitable.com/index/asciifull.gif

edited Sep 25, 2015 at 15:19

Rory McCrossan

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answered Sep 25, 2015 at 14:58

user5376767

1

1 Comment

user5376767 Over a year ago

using , instead of \x2c gives browser error Uncaught SyntaxError: Unexpected end of input

Rogthat Sinatra · Accepted Answer · 2019-07-18 13:14:06Z

0

If your trying to escape a throw error due to comas that you need in a non quoted could be string datatype. say you needed it that way post.example, + post.example,

  var comma =",";

post.example.concat(comma) + post.example.concat(comma)

Using concat method will concatenate any variable type.

edited Jul 18, 2019 at 13:14

answered Jul 17, 2019 at 13:37

Rogthat Sinatra

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