POST Method not working in Spring MVC

Question

I have created a login form

<form class="login100-form validate-form p-b-33 p-t-5" method="POST">
<div class="wrap-input100 validate-input" data-validate = "Enter username">
    <input class="input100" type="text" name="username" placeholder="User name">
    <span class="focus-input100" data-placeholder="&#xe82a;"></span>
</div>
<div class="wrap-input100 validate-input" data-validate="Enter password">
    <input class="input100" type="password" name="pass" placeholder="Password">
    <span class="focus-input100" data-placeholder="&#xe80f;"></span>
</div>
<div class="container-login100-form-btn m-t-32">
    <input class="login100-form-btn" type="button" onclick="location.href='eLibrary/login'" value="Login" >
</div>

And my controller function is

@RequestMapping(value = "/login", method = RequestMethod.POST)
public String login(HttpServletRequest request, HttpServletResponse response) {
    String userName = request.getParameter("username");
    String pass = request.getParameter("pass");
    return "list-books";
}

But, when I'm trying to login, it's giving error

HTTP Status 405 - Method Not Allowed

Request method 'GET' not supported

I even have tried

@PostMapping("/login")
public String login(HttpServletRequest request, HttpServletResponse response) {
    String userName = request.getParameter("username");
    String pass = request.getParameter("pass");
    return "list-books";
}

But in the above case, request.getParameter("username") is giving null.

Can anyone please help me out.

Adam Lesiak · Accepted Answer · 2018-04-25 09:44:27Z

1

Update the line:

<input class="login100-form-btn" type="button" onclick="location.href='eLibrary/login'" value="Login" >

with remove the onclick:

<input class="login100-form-btn" type="submit" value="Login" >

and update the FORM line to:

<form class="login100-form validate-form p-b-33 p-t-5" method="POST" action="eLibrary/login">

Onclick will always send a GET request. If you wanna do POST with javascript you have to use AJAX action.

edited Apr 25, 2018 at 9:44

answered Apr 25, 2018 at 9:42

Adam Lesiak

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2 Comments

amit_vickey Over a year ago

then how do you suggest me to handle the onclick part.?

Adam Lesiak Over a year ago

You have two choices: 1. Remove onclick and do standard POST action. 2: Use javascript xHttpRequest or one of the framework (eg. jQuery) to send post action. Examples: stackoverflow.com/questions/25881204/…

Nidhi257 · Accepted Answer · 2018-04-25 09:25:50Z

0

Update below line

<input class="login100-form-btn" type="button" onclick="location.href='eLibrary/login'" value="Login" >

with <input class="login100-form-btn" type="submit" onclick="location.href='eLibrary/login'" value="Login" >

answered Apr 25, 2018 at 9:25

Nidhi257

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6 Comments

amit_vickey Over a year ago

It's not giving any error now, but redirecting me to the same login page and not even going to the break-point when running in debug mode.

Nidhi257 Over a year ago

try writing return "/list-books"

amit_vickey Over a year ago

In my sevlet.xml I already have <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/view/" /> <property name="suffix" value=".jsp" /> </bean> So, "/" will automatically be prefixed

Nidhi257 Over a year ago

what url is updated while clicking on submit button?

amit_vickey Over a year ago

url is not changing, it seems it just is refreshing the page And when I'm simply clicking on "Login" button(without entering any data) then same Error-405 is coming

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