Javascript regex to check for at least 3 carets in a string

Question

I am requesting assistance with a regular expression to show that there are at least 3 carets in a string. I've tried using /\^/ but that only finds if the caret exists one time.

Example Data:

KEYWORD^HOSTNAME^MESSAGE^NUMBERS

And what regexes have you tried so far to solve the problem? — Luca Kiebel
– Luca Kiebel, Commented May 22, 2018 at 12:09
Possible duplicate of Count number of matches of a regex in Javascript — Andrew Morton
– Andrew Morton, Commented May 22, 2018 at 12:10
/\^/ but that only finds if it exists one time. How can I add that the care must be present 3 times in the string? — DWard
– DWard, Commented May 22, 2018 at 12:16

Emeeus · Accepted Answer · 2018-05-22 12:30:17Z

2

This expression should work:

(.*\^.*){3}

Example in javascript:

var str = "KEYWORD^HOSTNAME^MESSAGE^NUMBERS";
var patt = new RegExp(/(.*\^.*){3}/);
var res = patt.test(str);
console.log(res);

edited May 22, 2018 at 12:30

answered May 22, 2018 at 12:17

Emeeus

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3 Comments

DWard Over a year ago

I tried the expression that you provided but am receiving an invalid response. var string = "KEYWORD^HOSTNAME^MESSAGE^NUMBERS"; var re = new RegExp("/.*(.*\^.*){3,}.*/"); if (re.test(string)) { console.log("Valid"); } else { console.log("Invalid"); }

Emeeus Over a year ago

@Dward RegExp(/(.*\^.*){3}/); without ' " '

Emeeus Over a year ago

@misanthrop Thanks for improving the regex

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