I have a list which contains the following
a= [june,32,may,67,april,1,dec,99]
I want to sort only the numbers in descending order but it should display with corresponding pair:
Output Expected
----------------
dec,99,may,67,june,32,april,1
I tried to sort using a.sort(reverse=True) command in the list not getting the expected output,this one is confusing a lot.
You can use a list of tuples:
a = ['june', '32', 'may', '67', 'april', '01', 'dec', '99']
zipper = zip(a[::2], a[1::2])
res = sorted(zipper, key=lambda x: -int(x[1])) # or, int(x[1]) with reverse=True
print(res)
[('dec', '99'), ('may', '67'), ('june', '32'), ('april', '01')]
If you need to flatten, use itertools.chain:
from itertools import chain
res = list(chain.from_iterable(res))
['dec', '99', 'may', '67', 'june', '32', 'april', '01']
You can first create nested lists containing the month-value pair, apply sorted, and then flatten:
a= ['june',32,'may',67,'april',01,'dec',99]
new_a = sorted([[a[i], a[i+1]] for i in range(0, len(a), 2)], key=lambda x:x[-1], reverse=True)
final_a = [i for b in new_a for i in b]
Output:
['dec', 99, 'may', 67, 'june', 32, 'april', 1]
a = ['june',32,'may',67,'april',1,'dec',99]a = [x for s in [[b,a] for a,b in sorted([(a[i],a[i-1]) for i in range(len(a)) if i%2 == 1],reverse=True)] for x in s]