Go http proxy with auth

Question

I need to use a proxy with auth using PostForm method. If I use something like (simplified):

request, err := http.NewRequest("GET", url.String(), nil)
response, err := client.Do(request)

I can with ease do request.Header.Add("Proxy-Authorization", basicAuth) and it works fine. But now, I am editing third-party package, and I try to add proxy to the existing code:

    proxyStr := "http://proxy.com:8080"
    proxyURL, _ := url.Parse(proxyStr)

    transport := &http.Transport{
        Proxy: http.ProxyURL(proxyURL),
    }
    bot.Client = &http.Client{
        Transport: transport,
    }

    resp, err := bot.Client.PostForm(method, params)

    auth := "username:password"
    basicAuth := "Basic " + base64.StdEncoding.EncodeToString([]byte(auth)) 
    resp.Header.Add("Proxy-Authorization", basicAuth)

It does not work, and it fails, to my mind, at string resp.Header.Add("Proxy-Authorization", basicAuth). Proxy without auth works fine, in this example. Does anybody know, can I use proxy with auth in this case?

You are adding the authorization header to the response, not to the request. — Eelco
– Eelco, Commented Jul 4, 2018 at 14:50

Andrii Soluk · Accepted Answer · 2021-10-31 10:53:13Z

13

You can create the client once by using the following code. Then substitute your HTTP client in the third-party package.

&http.Client{
  Transport: &http.Transport{
    Proxy: http.ProxyURL(&url.URL{
      Scheme: "http",
      User:   url.UserPassword("username", "password"),
      Host:   "146.137.9.45:65233",
    }),
  },
}

or you can parse the URL as well

url, _ := url.Parse("http://username:[email protected]:65233")
&http.Client{
  Transport: &http.Transport{
    Proxy: http.ProxyURL(url),
  }
}

edited Oct 31, 2021 at 10:53

answered Jun 14, 2020 at 9:14

Andrii Soluk

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1 Comment

Nikolai Ehrhardt Over a year ago

this wont parse... ":" is separator for port

facumedica · Accepted Answer · 2018-07-04 15:03:08Z

7

You are trying to add a header to a response, which isn't what you send to the server but what you receive. You have to add headers and data to the request, which you have to assemble first and then execute it like this:

data := url.Values{} // the form data
data.Add("foo-key", "some data")
req, err := http.NewRequest("POST","https://yoururl", strings.NewReader(data.Encode()))
auth := "username:password"
basicAuth := "Basic " + base64.StdEncoding.EncodeToString([]byte(auth))
req.Header.Add("Proxy-Authorization", basicAuth)
req.Header.Add("Content-Type", "application/x-www-form-urlencoded")
resp, err := bot.Client.Do(req)

Then you just use the response (resp)

edited Jul 4, 2018 at 15:03

answered Jul 4, 2018 at 14:51

facumedica

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Comments

Oleg Sydorov · Accepted Answer · 2018-07-05 06:28:22Z

0

Thanks to all!

I found such a solution (may be it would be useful to someone):

// Uncomment to use proxy with auth
    /*
    proxyStr := "http://proxy.com:3128"
    proxyURL, _ := url.Parse(proxyStr)
    auth := "username:password"
    basicAuth := "Basic " + base64.StdEncoding.EncodeToString([]byte(auth))
    hdr := http.Header{}
    hdr.Add("Proxy-Authorization", basicAuth)
    transport := &http.Transport{
        Proxy: http.ProxyURL(proxyURL),
        ProxyConnectHeader: hdr,
    }

    bot.Client = &http.Client{
        Transport: transport,
    }
    */

    resp, err := bot.Client.PostForm(method, params)

answered Jul 5, 2018 at 6:28

Oleg Sydorov

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