How can I call a share compare function for array.sort in javascript?

Question

I am trying to call a shared comparer function from an array.sort to sort 2 different arrays.

if i have:

projects.sort(
        function(a, b){
          var x = a.name.toLowerCase();
          var y = b.name.toLowerCase();
          if (x < y) {return -1;}
          if (x > y) {return 1;}
          return 0;
        });

and

products.sort(
        function(a, b){
          var x = a.name.toLowerCase();
          var y = b.name.toLowerCase();
          if (x < y) {return -1;}
          if (x > y) {return 1;}
          return 0;
        });

how can i do this?

projects.sort(sortArray());
products.sort(sortArray());

Don't put the parentheses after sortArray: projects.sort(sortArray) — Heretic Monkey
– Heretic Monkey, Commented Jul 26, 2018 at 21:33

Peter Olson · Accepted Answer · 2018-07-26 21:33:48Z

3

Create a named function:

function compare(a, b){
  var x = a.name.toLowerCase();
  var y = b.name.toLowerCase();
  if (x < y) {return -1;}
  if (x > y) {return 1;}
  return 0;
}

Then you can reference this function when you call sort:

projects.sort(compare);
products.sort(compare);

answered Jul 26, 2018 at 21:33

Peter Olson

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1 Comment

Tony Gregg Over a year ago

thank you, Peter! for some reason when i tried this it didn't work. It's working now, beautifully. much appreciated for your quick response.

TuringCreep · Accepted Answer · 2018-07-26 21:53:14Z

0

function sortItems(a,b) {
  var   x = a.name.toLowerCase(),
        y = b.name.toLowerCase()

  return x.localeCompare(y);
 }

// Then use this
projects.sort(sortItems);
products.sort(sortItems);

answered Jul 26, 2018 at 21:53

TuringCreep

595 bronze badges

1 Comment

Nic3500 Over a year ago

Please add an explanation to your answer, it will help users with their future searches.

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