converting str to int in list comprehension [duplicate]

Question

I have a list with years as strings but there are few missing years which are represented as empty strings.

I am trying to convert those strings to integers and skip the values which can't be converted using list comprehension and try and except clause?

birth_years = ['1993','1994', '' ,'1996', '1997', '', '2000', '2002']

I tried this code but it's not working.

try:
    converted_years = [int(year) for year  in birth_years]
except ValueError:
    pass

required output:
converted_years = ['1993','1994','1996', '1997', '2000', '2002']

You can either use a list comprehension or a try ... except. Not both. — Aran-Fey
– Aran-Fey, Commented Aug 8, 2018 at 11:24
You can't use a try-except in a comprehension, you could do it in a regular for loop — Chris_Rands
– Chris_Rands, Commented Aug 8, 2018 at 11:24
Of course you could create a separate function that perform the try-except and then call that in the comprehension but I don't see any point (for this simple example at least) — Chris_Rands
– Chris_Rands, Commented Aug 8, 2018 at 11:28
write a function like def my_f: try: return int(year); except ValueError: pass then in the comprehension [my_f(year) for year in birth_years if my_f(year) ] (the pass means the fasly None is returned when the error is encountered, not this isn't the most efficient to call the function twice) — Chris_Rands
– Chris_Rands, Commented Aug 8, 2018 at 11:43

Ankit S · Accepted Answer · 2018-08-08 11:24:44Z

6

[int(year) for year in birth_years if year.isdigit()]

answered Aug 8, 2018 at 11:24

Ankit S

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Mohit Solanki · Accepted Answer · 2018-08-08 11:22:13Z

2

converted_years = [int(year) for year in birth_years if year]

answered Aug 8, 2018 at 11:22

Mohit Solanki

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Madhan Varadhodiyil · Accepted Answer · 2018-08-08 11:23:21Z

1

converted_years = [int(x) for x in birth_years if x.isdigit()]

answered Aug 8, 2018 at 11:23

Madhan Varadhodiyil

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