How to filter a listview?

Question

I have a list view and i want to show records by filter suppose i have an array list called expenseList. in expenseList i am able to filter single item like this

 if (!dealerexpautoa.getText().toString().equals("")){
                        ArrayList<ExpenseStatusModel.Expense> expensetypeList= new ArrayList<>();

                        for (int i = 0; i < expenseList.size(); i++)
                        {
                            if (expenseList.get(i).getDealerName().equalsIgnoreCase(dealerexpautoa.getText().toString())) {

                                expensetypeList.add(expenseList.get(i));
                            }
                        }
                        adapterExpenseView.filterList(expensetypeList);

                    }

here getting the perfect output but when i need to perform same task with two string then it is not getting me the right out put

i have an EditText and Spinner i want to compare both and print in list view

else if(!spn.getSelectedItem().toString().equals("Select Type")
                            && !dealerexpautoa.getText().toString().equals("")){
                        ArrayList<ExpenseStatusModel.Expense> expensetypeList= new ArrayList<>();

                        for (int i = 0; i < expenseList.size(); i++)
                        {
                            if (expenseList.get(i).getDealerName().equalsIgnoreCase(dealerexpautoa.getText().toString()) &&
                                    expenseList.get(i).getExpenseType().equalsIgnoreCase(spn.getSelectedItem().toString())) {

                                expensetypeList.add(expenseList.get(i));
                            }
                        }
                        adapterExpenseView.filterList(expensetypeList);

                    }

navylover · Accepted Answer · 2018-09-15 06:07:01Z

1

The condition expression in if branch is:

!dealerexpautoa.getText().toString().equals("")

and the condition expression in else branch is

!spn.getSelectedItem().toString().equals("Select Type")
                            && !dealerexpautoa.getText().toString().equals("")

this two expressions are not mutually exclusive, only dealerexpautoa text is equal empty string, it could enter into else branch, but in else branch,the condition needs dealerexpautoa text not equal empty string, so this is contradictory.

answered Sep 15, 2018 at 6:07

navylover

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2 Comments

Sachin Solanki Over a year ago

so how to perform this task any example? i know that only first condition is checked by if... but the thing is i show this code for how i tried

navylover Over a year ago

unclear total login, try using two independent if clause, no else branch.

Kevin Kurien · Accepted Answer · 2018-09-15 06:09:41Z

1

you forgot to write if in your else statement

else if(!spn.getSelectedItem().toString().equals("Select Type")
                            && !dealerexpautoa.getText().toString().equals("")){
                        ArrayList<ExpenseStatusModel.Expense> expensetypeList= new ArrayList<>();

                        for (int i = 0; i < expenseList.size(); i++)
                        {
                            if (expenseList.get(i).getDealerName().equalsIgnoreCase(dealerexpautoa.getText().toString()) &&
                                    expenseList.get(i).getExpenseType().equalsIgnoreCase(spn.getSelectedItem().toString())) {

                                expensetypeList.add(expenseList.get(i));
                            }
                        }
                        adapterExpenseView.filterList(expensetypeList);

                    }

answered Sep 15, 2018 at 6:09

Kevin Kurien

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1 Comment

Sachin Solanki Over a year ago

i am sorry i forgot to write if in the question but actually in my project it is else if only

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