How to show default url if variable value is empty in laravel blade

Question

I know that for a normal variable I can use something like {{ $vid->shares ? : '0' }} to show default information in Laravel 5.7 blade files.

Now I need to show image source, which I am doing like <img src="{{ url($vid->thumb_file) }}"> this works fine until I hit a empty value.

is there anything to avoid such case by adding a default fallback image URL? Or "if else" is only a better solution?

Something like {{ url($vid->thumb_file) ?: url('/images/video-thumbnail.png') }} which is not working.

Check it like: $vid->thumb_file ? url($vid->thumb_file) : url('/images/video-thumbnail.png') — Hiren Gohel
– Hiren Gohel, Commented Nov 27, 2018 at 6:23
Yes, that works. <img src="{{ $vid->thumb_file ? url($vid->thumb_file) : url('/images/video-thumbnail.png') }}" alt="" class="img-fluid"> — Ramesh Navi
– Ramesh Navi, Commented Nov 27, 2018 at 6:28

Hiren Gohel · Accepted Answer · 2018-11-27 06:35:55Z

3

You can use like below:

<img src="{{ $vid->thumb_file ? url($vid->thumb_file) : url('/images/video-thumbnail.png') }}" alt="" class="img-fluid">

This is as same as Ternary Operator you used above: {{ $vid->shares ?: '0' }}

You can also check it in your controller, like:

if (file_exists(public_path() . '/images/' . $vid->image)) {
    $img = $vid->image;
} else {
    $img = '/images/video-thumbnail.png';
}

Hope this helps!

edited Nov 27, 2018 at 6:35

answered Nov 27, 2018 at 6:30

Hiren Gohel

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MD. Jubair Mizan · Accepted Answer · 2018-11-27 06:30:07Z

2

You can use this way:

{{ isset($vid->thumb_file) ? $vid->thumb_file : url('/images/video-thumbnail.png') }}

<img src="{{ isset($vid->thumb_file) ? $vid->thumb_file : url('/images/video-thumbnail.png') }}" alt="" class="img-fluid">

answered Nov 27, 2018 at 6:30

MD. Jubair Mizan

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