Using bash to parse .env file and inject it to command line

Question

I am using kubernetes and trying to call the following command:
kubectl set env deployment/server A=a B=b ...etc My env variables are located in .env file, and each value can contain spaces, non-escaped chars, comments, empty lines and so on:

## Common variables
NODE_ENV=production


## Server variables
SERVER_PORT=8009
CORS_ORIGIN=https://www.example.io,http://www.example.io,http://localhost:3000
SESSION_SECRET=/qm%7HLw"pk(8@"pja#I9CbN#2Lg[%d>5{CDA_9g|ZvZmuZ$]=';EhA#g+C;1>&

I am trying to parse the .env file so that I can integrate it in the command:

kubectl set env deployment/server $(do magic with .env file to extract the escaped variables)

Tried grep -v '^#' .env | xargs but it doesn't work with characters that need escaping or quotes. My bash abilities are not the strongest right now. Any idea how to solve this?

@prd New to kubernetes and didn't find well toturial that explains how to write .yml configs. Currency doing everyting via cli and kubectl. — Naor
– Naor, Commented Feb 13, 2019 at 8:50

Alberti Buonarroti · Accepted Answer · 2019-02-13 09:02:44Z

2

cat .env | grep -v '^#\|^$' | xargs -0 echo | tr '\n' ' '

This would print everything in one line: NODE_ENV=production SERVER_PORT=8009 CORS_ORIGIN=https://www.example.io,http://www.example.io,http://localhost:3000 SESSION_SECRET=/qm%7HLw"pk(8@"pja#I9CbN#2Lg[%d>5{CDA_9g|ZvZmuZ$]=';EhA#g+C;1>&

I am not sure if you need to keep the VAR= or if you also would like to get rid of that (pipe into sed or awk in the end then and replace it with whatever you need)

answered Feb 13, 2019 at 9:02

Alberti Buonarroti

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5 Comments

Naor Over a year ago

Thanks, this is a progress. I actually need the values escaped and wrapped with quotes since values contains slashes and quotes, this is the big issue. Any idea how to handle that?

Alberti Buonarroti Over a year ago

| sed 's/=/="/g' | sed 's/ /" /g' this would add quotes to all your values. But you also need to look into your values and escape certain chars with a backslash \ ?

Naor Over a year ago

Exactly. Any idea how to do it?

Alberti Buonarroti Over a year ago

Yeah, you can use one complex sed or just chain several ones to maintain readability. First add a backslash to all $-chars, then to all %-chars...change the char to whatever you need. Use a backslash in case it also used in Regex to escape it or sed will interpret it as a regex flag. sed 's/\$/\\$/g' | sed 's/\%/\\%/g' If this is what you meant I will update my main answer to make it more readable.

Naor Over a year ago

Thanks, looks like it is something I can continue with.

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