Java Transformer error: Could not compile stylesheet

Question

I'm want to transform a XML with XSLT in Java. For that I'm using the javax.xml.transform package. However, I get the exception javax.xml.transform.TransformerConfigurationException: Could not compile stylesheet. This is the code I'm using:

public static String transform(String XML, String XSLTRule) throws TransformerException {

    Source xmlInput = new StreamSource(XML);
    Source xslInput = new StreamSource(XSLTRule);

    TransformerFactory tFactory = TransformerFactory.newInstance();
    Transformer transformer = tFactory.newTransformer(xslInput); // this is the line that throws the exception

    Result result = new StreamResult();
    transformer.transform(xmlInput, result);

    return result.toString();
}

Note that I marked the line which throws the exception.

When I enter the method, the value of XSLTRule is this:

<xsl:stylesheet version='1.0'
 xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
 xmlns:msxsl='urn:schemas-microsoft-com:xslt'
 exclude-result-prefixes='msxsl'
 xmlns:ns='http://www.ibm.com/wsla'>
    <xsl:strip-space elements='*'/>
    <xsl:output method='xml' indent='yes'/>
    <xsl:template match='@* | node()'>
        <xsl:copy>
            <xsl:apply-templates select='@* | node()'/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="/ns:SLA
                            /ns:ServiceDefinition
                               /ns:WSDLSOAPOperation
                                  /ns:SLAParameter[@name='Performance']"/>
</xsl:stylesheet>

It is javax.xml.transform.TransformerConfigurationException. I edited my original post, it is there now. — Ivan
– Ivan, Commented Mar 29, 2011 at 12:36
Because that element should be deleted. It finds the element, but doesn't copy it. This XSLT should work, I used it before while I was working in .NET. — Ivan
– Ivan, Commented Mar 29, 2011 at 12:45

MarcoS · Accepted Answer · 2011-03-29 13:41:01Z

11

The constructor

public StreamSource(String systemId)

Construct a StreamSource from a URL. I think you're passing the content of the XSLT instead. Try this:

File xslFile = new File("path/to/your/xslt");
TransformerFactory factory = TransformerFactory.newInstance();
Templates xsl = factory.newTemplates(new StreamSource(xslFile));

You must also set the OutputStream that your StreamResult will write to:

ByteArrayOutputStream baos = new ByteArrayOutputStream();
Result result = new StreamResult(baos);
transformer.transform(xmlInput, result);
return baos.toString();

edited Mar 29, 2011 at 13:41

answered Mar 29, 2011 at 12:50

MarcoS

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5 Comments

Michael Kay Over a year ago

Alternatively, just change new StreamSource(XSLTRule) to new StreamSource(new StringReader(XSLTRule))

Ivan Over a year ago

thanks a lot! but i still have a problem with the Result result = new StreamResult();. What to do there?

MarcoS Over a year ago

@Ivan: what problem do you have with Result result = new StreamResult();?

Ivan Over a year ago

@Michael For the line transformer.transform I get this exception: javax.xml.transform.TransformerException: Result object passed to ''{0}'' is invalid.I did the same thing for the variable XML as for XSLTRule.

MarcoS Over a year ago

@Ivan: I see: I've edited my answer to address that problem too.

Nishan · Accepted Answer · 2011-03-29 13:50:30Z

1

You will have to contruct a stream from the xslt string you have and then use it as the stream source

InputStream xslStream = new ByteArrayInputStream(XSLTRule.getBytes("UTF-8"));
Source xslInput = new StreamSource(xslStream);

To get the result to a string :

    ByteArrayOutputStream bos = new ByteArrayOutputStream();
    Result result = new StreamResult(bos);
    transformer.transform(xmlInput, result);
    String s = new String(bos.toByteArray());
    System.out.println(s);

edited Mar 29, 2011 at 13:50

answered Mar 29, 2011 at 12:52

Nishan

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1 Comment

Ivan Over a year ago

thanks a lot! but i still have a problem with the Result result = new StreamResult();. What to do there?

Vijay Vyawhare · Accepted Answer · 2015-10-08 13:33:20Z

0

To use XSLTC, put xalan.jar(2.5), serializer.jar, xml-apis.jar, and xercesImpl.jar on your classpath .

answered Oct 8, 2015 at 13:33

Vijay Vyawhare

1

1 Comment

Lambart Over a year ago

Don't do this. All those packages (from the Xerces project) have been abandoned since 2010. The code now lives in the JVM.

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