I have a dict that looks something like this:
d = {'a': 'b', 'c': 'd'}
Now, when I make a str out of it using str(d) i get
>> "{'a': 'b', 'c': 'd'}"
but I need it to look like this:
>> "a=b; c=d; "
I created this piece of code that does this:
b = ''
for k, v in d.items():
b += str(k) + '=' + str(v) + '; '
Is there a way to achieve the same effect, but doing it with an inline operation or some other neater way, without using the for loop?
Her is another way using ''.join():
';'.join(map('='.join, d.items()))
Returns:
'a=b;c=d'
This assumes the last ; is redundant. If not you could get the "exact" output as this: ''.join([f'{k}={v}; ' for k,v in d.items()])
Timings:
%timeit ';'.join(map('='.join, d.items())) #1000000 loops,best of 3: 810 ns per loop
%timeit ';'.join(['='.join(x) for x in d.items()]) #1000000 loops,best of 3: 956 ns per loop
%timeit ';'.join([f'{k}={v}' for k,v in d.items()]) #1000000 loops,best of 3: 872 ns per loop
[] is actually quicker.Like this:
d = {'a': 'b', 'c': 'd'}
strd = " ".join("{}={};".format(x, y) for x, y in d.iteritems()) # items() if python3
strd:
"a=b; c=d;"
If you're not too attached with = sign, you can convert it into a json string
import json
json.dumps({'a': 'b', 'c': 'd'})
This would work for nested dictionaries as well.
You can use the magic method __repr__() to get the string representation of an object:
d = {'a': 'b', 'c': 'd'}
d.__repr__()
# {'a': 'b', 'c': 'd'}
d.__repr__().replace(': ', '=').strip('{}')
# 'a'='b', 'c'='d'
''.join()