CakePHP - how to use Helpers to make an image link with target="_blank"

Question

This seems like it should be simple, but I'm new to CakePHP. Maybe it's just something I should write in good ole HTML, but - was hoping to find out how do to this with CakePHP's HTML helper.

I just want an image link that has target="_blank".

This is what I tried:

<?php echo $this->Html->link($this->Html->image('tmp/728x90.jpg',
    array('alt'=>'advertisement', 'height'=>'90', 
    'width'=>'728')),'http://www.google.com', array('target'=>'_blank')); ?>

(all in one line - just broke up for ease of viewing)

But when I do this, I get this:

<a href="http://www.google.com" target="_blank">&lt;img src=&quot;/img/tmp/728x90.jpg&quot; alt=&quot;advertisement&quot; height=&quot;90&quot; width=&quot;728&quot; /&gt;</a>

Any help is greatly appreciated.

Answer (thanks deceze)

<?php 

$image = $this->Html->image(
    'tmp/300x600.jpg', 
    array(
        'alt'=>'advertisement', 
        'height'=>'600', 
        'width'=>'300'
    )
);

echo $this->Html->link(
    $image,
    'http://www.google.com', 
    array(
        'target'=>'_blank', 
        'escape' => false
    )
); ?>

Answer is very useful, thanks for sharing. keep it up!

Aditya P Bhatt
– Aditya P Bhatt

2014-03-13 08:55:43 +00:00
Commented Mar 13, 2014 at 8:55 — Aditya P Bhatt
– Aditya P Bhatt, Commented Mar 13, 2014 at 8:55

andrewsi · Accepted Answer · 2012-10-10 12:11:47Z

12

<?php echo $this->Html->link($this->Html->image('fb2.jpg',array('alt'=>'facebook', 'height'=>'90','width'=>'728')),'http://www.facebook.com', array('target'=>'_blank','escape'=>false)); ?>

edited Oct 10, 2012 at 12:11

andrewsi

10.7k132 gold badges37 silver badges52 bronze badges

answered Oct 10, 2012 at 12:10

sourav

1211 silver badge3 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Samuel Liew · Accepted Answer · 2018-12-22 04:37:29Z

3

You need to tell HtmlHelper::link not to HTML escape the input.
This is all very well documented in the manual.

edited Dec 22, 2018 at 4:37

Samuel Liew

79.5k112 gold badges173 silver badges318 bronze badges

answered Mar 31, 2011 at 4:02

deceze♦

525k89 gold badges807 silver badges954 bronze badges

Comments

Shrish Shrivastava · Accepted Answer · 2015-07-03 11:12:59Z

1

The exact code will be like this

  <?php 
         echo $this->Html->link(
                    $this->Html->image('tmp/728x90.jpg',
                                         array(
                                        'alt'=>'advertisement', 'height'=>'90',
                                        'width'=>'728')
                                       ),
                                    'http://www.google.com',
                                    array(
                                       'target'=>'_blank',
                                       'escape'=>false)
                                ); 
?>

answered Jul 3, 2015 at 11:12

Shrish Shrivastava

5856 silver badges20 bronze badges

Comments

user470714 · Accepted Answer · 2011-03-31 03:37:52Z

0

You need to use the Html->image . Check it out:

http://book.cakephp.org/view/1441/image

answered Mar 31, 2011 at 3:37

user470714

2,8881 gold badge31 silver badges34 bronze badges

3 Comments

Dave Over a year ago

I have used that - and in fact, I'm using it in my code above. Please give an example if I'm doing something wrong - the link you gave has no information regarding the target attribute for a link.

user470714 Over a year ago

It's right in the manual: <?php echo $this->Html->image("recipes/6.jpg", array( "alt" => "Brownies", 'url' => array('controller' => 'recipes', 'action' => 'view', 6) )); ?> You see you use the url option instead of the calling html->image inside of image->link

Dave Over a year ago

@user470714 - While I do appreciate your attempt at answering, I recommend reading the question before answering next time. I did not ask how to make a linked image - I asked how to make a linked image open in a new tab/window with target="_blank". Neither your answer, nor your comment addressed my question.

Phil123 · Accepted Answer · 2013-06-19 18:35:59Z

0

Like mentioned in the Cook Book, you can use the 'url' option of the image method:

echo $this->Html->image("recipes/6.jpg", array(
   'alt' => "Brownies",
   'url' => array('controller' => 'recipes', 'action' => 'view', 6)
));

answered Jun 19, 2013 at 18:35

Phil123

8711 bronze badges

Comments

Archit Patel · Accepted Answer · 2011-04-05 13:04:26Z

-1

echo $html->link("more",array('controller' => 'users', 'action' => 'index/welcome'), array('style'=>'_blank'), false, false);?> image('more-arrow.png', array('alt' => 'more','height'=>'11','width'=>'17'))?>

answered Apr 5, 2011 at 13:04

Archit Patel

496 bronze badges

2 Comments

Dave Over a year ago

I don't think that is right. For one, it's got two php close tags, and two, it's setting "style" to _blank instead of target. I appreciate your taking the time to answer but this question has already been answered. :)

Fr0zenFyr Over a year ago

:] I'm having a good laugh looking at this code. Nice refresher from the hectic day.

Collectives™ on Stack Overflow

CakePHP - how to use Helpers to make an image link with target="_blank"

6 Answers 6

Comments

Comments

Comments

3 Comments

Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

Comments

Comments

Comments

3 Comments

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related