PHP REGEX preg_match_all every line after a particular line

Question

Here is the sample string with my regex and code:

$str = "Supp Fees:
----------
Oral Glucose
Glucagon
OXYGEN";

$ptn = "/----------(?:\r\n(.+))+/m";
preg_match_all($ptn,$str,$matches);

echo"<pre>";
print_r($matches);
echo"</pre>";

I'm trying to match every line after '----------' the pattern above only returns the first line (Oral Glucose). I can repeat the '\r\n(.+)' part and return another line but there is no telling how many lines there will be.

Thanks!

Ben Rowe · Accepted Answer · 2011-04-04 23:35:26Z

2

You could do this without regex:

$data = substr($str, strpos($str, '----------') + 10);
$matches = explode("\r\n", $data);

answered Apr 4, 2011 at 23:35

Ben Rowe

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1 Comment

jreed121 Over a year ago

You mean solving a string problem without REGEX!>!>!>!?! lol, it's funny how I've been using REGEX so much lately I didn't even consider using php functions. thanks.

Demian Brecht · Accepted Answer · 2011-04-04 23:37:50Z

1

<?php

$str = "Supp Fees:
----------
Oral Glucose
Glucagon
OXYGEN";


$str = explode('----------', $str);
preg_match_all("/[^\r\n].*/", $str[1], $matches);

echo"<pre>";
print_r($matches);
echo"</pre>";

?>

?

answered Apr 4, 2011 at 23:37

Demian Brecht

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