How to search with xpath in given html element?

Question

I have the following code:

    HtmlPage searchPage = mainWebClient.getPage(searchUrl);
    List<HtmlListItem> lis = searchPage.getByXPath("//div[@id='mainContent']//li[contains(@id, 'results-listing')]");
    for (HtmlListItem li : lis) {
        List<Object> linkXPath = li.getByXPath("//a[contains(@class, 'itemlink')]/@href");
    }

On the fourth line I want to search with XPath only in the li and not in the whole page. If i put there: searchPage.getByXPath("//a[contains(@class, 'itemlink')]/@href"); the result will be the same. How to search not in the whole document but only in the li ?

Please share you html code.

Sudha Velan
– Sudha Velan

2019-04-02 06:35:53 +00:00
Commented Apr 2, 2019 at 6:35 — Sudha Velan
– Sudha Velan, Commented Apr 2, 2019 at 6:35

supputuri · Accepted Answer · 2019-04-01 20:51:01Z

1

Use the index rather for each.

searchPage.getByXPath("(//div[@id='mainContent']//li[contains(@id, 'results-listing')])[" + index + "]//a[contains(@class, 'itemlink')]/@href");

edited Apr 1, 2019 at 20:51

answered Apr 1, 2019 at 19:58

supputuri

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1 Comment

supputuri Over a year ago

Updated the answer to use the index directly in the xpath. You have to change the loop.

Alejandro · Accepted Answer · 2019-04-01 21:45:51Z

1

Your problem came because the use of an absolute location path (basicaly, a location path starting with /).

You need a relative location path. Use:

descendant::a[contains(@class, 'itemlink')]/@href

Or with abbreviations

.//a[contains(@class, 'itemlink')]/@href

answered Apr 1, 2019 at 21:45

Alejandro

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