JavaScript: Add space between Char and Number with Regex

Question

Hello I have a plate number BZ8345LK and want convert to BZ 8345 LK (adding space between char and number).

I tried with this Regex but not working, only space first char with number. Ex BZ 8345LK, the 'LK' keep not space with number.

var str = 'BZ8345LK';
str.replace(/[^0-9](?=[0-9])/g, '$& ');
# return BZ 8345LK, I want BZ 8345 LK

here is explained why stackoverflow.com/questions/1144783/… — GrafiCode
– GrafiCode, Commented May 31, 2019 at 9:34

Code Maniac · Accepted Answer · 2019-08-31 05:43:26Z

6

You can use this regex

[a-z](?=\d)|\d(?=[a-z])

[a-z](?=\d) - Match any alphabet followed by digit
| - Alternation same as logical OR
\d(?=[a-z]) - Any digit followed by alphabet

let str = 'BZ8345LK'

let op = str.replace(/[a-z](?=\d)|\d(?=[a-z])/gi, '$& ')

console.log(op)

edited Aug 31, 2019 at 5:43

answered May 31, 2019 at 9:34

Code Maniac

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5 Comments

Puyup Over a year ago

This best choice in dynamic text input like on change.

Puyup Over a year ago

Can you force remove extra space in number BZ 83 45 LK to BZ 8345 LK

Puyup Over a year ago

If number format BZ83 45LK, how to keep output BZ 8345 LK

bobble bubble Over a year ago

@Puyup First strip out the spaces then use the answer.

Code Maniac Over a year ago

@Puyup you can simply remove all the space str.replace(/\s+/g,'')

CertainPerformance · Accepted Answer · 2019-05-31 09:33:44Z

2

You should alternate with the other possibility, that a number is followed by a non-number:

var str = 'BZ8345LK';
console.log(str.replace(/[^0-9](?=[0-9])|[0-9](?=[^0-9])/g, '$& '));

answered May 31, 2019 at 9:33

CertainPerformance

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1 Comment

Puyup Over a year ago

If used in text input with onChange this code add more extra space each char and number.

nanndoj · Accepted Answer · 2019-05-31 09:41:00Z

0

An anoher option is to use:

^[^\d]+|[\d]{4}

Search for any not numeric character [^\d] followed by 4 numeric [\d]{4} characters

const str = 'BZ8345LK'
let answer = str.replace(/^[^\d]+|[\d]{4}/gi, '$& ')
console.log(answer)

answered May 31, 2019 at 9:41

nanndoj

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Comments

Yves Kipondo · Accepted Answer · 2019-05-31 10:10:01Z

0

Try with this

var str = "BZ8345LK";
var result = str.replace(/([A-Z]+)(\d+)([A-Z]+)/, "$1 $2 $3");
console.log(result);

answered May 31, 2019 at 10:10

Yves Kipondo

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