Date format transform in XSLT

Question

I want to transform XML value to date format.

Input:

<pub-date type="date">
    <day>14</day>
    <month>02</month>
    <year>2019</year>
</pub-date>

The output should be:

<dateformat name="Date" value="February 14, 2019"/>

Tried code :

<xsl:template name="insert-date">
    <dateformat name="Date">
        <xsl:attribute name="value">
            <xsl:value-of select="descendant::pub-date[@type='date']/concat(month,' ',day,', ',year)"/>
        </xsl:attribute>
    </tps:fieldSet>
</xsl:template>

But I am getting month as 02. I want to transform it into February. How can I change my code to get the desired output.

The answer depends on what version of XS:LT your processor supports - cf. stackoverflow.com/questions/57145609/… — michael.hor257k
– michael.hor257k, Commented Jul 23, 2019 at 4:59

michael.hor257k · Accepted Answer · 2019-07-23 05:47:57Z

1

IN XSLT 2.0, you could do a one liner:

<dateformat name="Date" value="{format-date(xs:date(concat(year, '-', month, '-', day)), '[MNn] [D], [Y]')}"/>

Demo: https://xsltfiddle.liberty-development.net/bFN1yac

Note that this assumes that both your day and month are zero-padded to 2 digits.

edited Jul 23, 2019 at 5:47

answered Jul 23, 2019 at 5:16

michael.hor257k

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