Compare 2 different arrays with same indexer but different amount of values in

Question

looking for your help.

I do have 2 arrays

a = [["01000340001001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 27, "Aleksandra ─īaka iela 110, R─½ga"], ["01000340002001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 15, "Aleksandra ─īaka iela 108, R─½ga"], ["01000340002002", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 4, "Aleksandra ─īaka iela 108, R─½ga"], ["01000340002005", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108B, R─½ga"], ["01000340002006", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108, R─½ga"], ["01000340002006", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108B, R─½ga"], ["01000340002008", 0, 1274, "Citas, iepriek┼Ī neklasific─ōtas, ─ōkas", "Nojume", 0, nil]]

Another one

b = [["01000340002001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 15], ["01000340002002", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 4], ["01000340002006", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1]]

I need to remove from a those arrays, that are in b by indexers as i think(e.g. remove duplicated).

What i was trying is to do this

all = []
all = a.collect {|key, value | key} - b.collect {|key, value | key}
# ["01000340002005", "01000340001001", "01000340002008"]

And then select arrays that i need

a.select { |key, value| key == b }
# ["01000340002008", 0, 1274, "Citas, iepriek┼Ī neklasific─ōtas, ─ōkas", "Nojume", 0, nil]

As outcome i get only 1 array, but should 3.

Could someone please suggest me how to make it work? :)

demir · Accepted Answer · 2019-09-23 10:53:14Z

1

Try this:

b_indexes = b.map(&:first)
a.delete_if { |arr| b_indexes.include?(arr.first) }
#~> [
      ["01000340001001", 0, 1122, "Triju vai vair─üku dz─½vok─╝u m─üjas", "Dz─½vojam─ü ─ōka", 27, "Aleksandra ─īaka iela 110, R─½ga"],
      ["01000340002005", 0, 1252, "Noliktavas, rezervu─üri, bunkuri un silosi", "Noliktava", 1, "Aleksandra ─īaka iela 108B, R─½ga"],
      ["01000340002008", 0, 1274, "Citas, iepriek┼Ī neklasific─ōtas, ─ōkas", "Nojume", 0, nil]
    ]

edited Sep 23, 2019 at 10:53

answered Sep 23, 2019 at 10:44

demir

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iGian · Accepted Answer · 2019-09-23 12:18:16Z

0

It seems that elements of a differs from elements of b for having a string more as last element.

So, you could just Array#reject! comparing the whole element of b:

a.reject! { |e| b.include? e[0...-1] }

But if only the first element of each nested array is the signal, mapping b against the first element before and then rejecting elements based on that map is the correct way.

Note that Array#reject! affects the original array.

answered Sep 23, 2019 at 12:18

iGian

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steenslag · Accepted Answer · 2019-09-23 14:24:25Z

0

assoc is nice for this:

p b.map{|ar| a.assoc(ar.first)}

answered Sep 23, 2019 at 14:24

steenslag

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