Node.js - Extracting part of the URL

Question

In my node.js server i have a URL variable.

It is either in the form of "https://www.URL.com/USEFUL_PART/blabla", or "URL.com/USEFUL_PART/blabla".

From this, i want to extract only the 'USEFUL_PART' information.

How do i do that with Javascript?

I know there are two ways to do this, one with vanilla js and one with regular expressions. I searched the web but i only found SO solutions to specific questions. Unfortunately, i coulnd't find a generic tutorial i could replicate or work out my solution.

This is extremely common in http framework routing, you could checkout express or hapi to see how they handle this :) — dm03514
– dm03514, Commented Oct 5, 2019 at 18:02

Brad · Accepted Answer · 2019-10-05 18:18:16Z

2

Since you're using Express, you can specify the part of the URL you want as parameters, like so:

app.get('/:id/blabla', (req, res, next) => {
  console.log(req.params); // Will be { id: 'some ID from the URL']
});

See also: https://expressjs.com/en/api.html#req.params

answered Oct 5, 2019 at 18:18

Brad

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fist ace · Accepted Answer · 2019-10-05 19:16:36Z

2

Hey if you are using express then you can do something like this

app.get('/users/:id/blabla',function(req, res, next){
   console.log(req.params.id);
 }

Another way is to use javascript replace and split function

str = str.replace("https://www.URL.com/", "");
str = str.split('/')[0];

answered Oct 5, 2019 at 19:16

fist ace

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Stephan Thierry · Accepted Answer · 2019-10-05 18:08:35Z

1

In Node.js you can use "URL"
https://nodejs.org/docs/latest/api/url.html

const myURL = new URL('https://example.org/abc/xyz?123');
console.log(myURL.pathname);
// Prints /abc/xyz

answered Oct 5, 2019 at 18:08

Stephan Thierry

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Code Maniac · Accepted Answer · 2019-10-05 18:06:02Z

1

One way is to check whether the url starts with http or https, if not then manually add http, parse the url using the URL api, take the patname from parsed url, and get the desired part

let urlExtractor = (url) =>{
  if(!/^https?:\/\//i.test(url)){
    url = "http://" + url
  }
  let parsed = new URL(url)
  return parsed.pathname.split('/')[1]
}

console.log(urlExtractor("https://www.URL.com/USEFUL_PART/blabla"))
console.log(urlExtractor("URL.com/USEFUL_PART/blabla"))

answered Oct 5, 2019 at 18:06

Code Maniac

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2 Comments

user1584421 Over a year ago

If it doesn't contain ('http' OR 'https') it will add 'http' OK. But what if it contains 'http'? Will this code put an 'https' before it?

Code Maniac Over a year ago

@user1584421 no it will add only when the http or https is missing at start

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