I know how to convert this:
const keys = [1, 2, 3];
To this:
[{key: 1, val: "q"}, {key: 2, val: "w"}, {key: 3, val: "e"}]
With a single mapping statement:
keys.map((x, i) => ({key: x, val: "qwe".charAt(i)}));
But I would actually like to get this:
{1: "q", 2: "w", 3: "e"}
Is there a neat way to do this in a single statement similar to the one above?
You can use reduce:
keys.reduce((accumulator, value, index) => { accumulator[index] = "qwe".charAt(index); return accumulator; }, {})
var a = (b) => b = 10 so a(5) returns 10
reduce completely. You need to return the actual object, as mentioned, as shown in my comment, and another answer.Ahhh, got it:
const objects = Object.assign({}, ...keys.map((x, i) => ({[x]: "qwe".charAt(i)})));
Though I would be happy to hear other suggestions as well as any notes on this one...
You can use reduce, and empty object as the initial value for the accumulator and insert property-value pairs on it:
const keys = [1, 2, 3];
let result = keys.reduce((obj, key, idx) => { obj[key] = 'qwe'[idx]; return obj }, {});
console.log(result)Here is my solution.
const keys = [1, 2, 3];
const vals = "qwe";
const result = keys.reduce((prev, cur, idx) => ({
...prev,
[cur]: vals[idx]
}), {});
[1, 2, 3].reduce((p, c, i) => (p[c] = "qwe"[i], p), {});, alternative:Object.fromEntries([1, 2, 3].map((e, i) => [e, "qwe"[i]]));Object.assign, so i think we got all the common ways. Wonder if there are some unfeasible but fun ways.